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Drawing Data Matrix in Objective-C N minutes

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DATE + n/24/60 DATE + n/1440 DATE + NUMTODSINTERVAL(n,'minute')
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N hours
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DATE + n/24 DATE + NUMTODSINTERVAL(n,'hour')
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N days
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DATE + n
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N weeks
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DATE + 7*n
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CHAPTER 12 DATATYPES
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Unit of Time
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N months
Operation
ADD_MONTHS(DATE,n) DATE + NUMTOYMINTERVAL(n,'month')
Description
You may use the ADD_MONTHS built-in function or add an interval of N months to the DATE. Please see the important caveat noted shortly regarding using month intervals with DATEs. You may use the ADD_MONTHS built-in function with 12*n to add or subtract N years. Similar goals may be achieved with a year interval, but please see the important caveat noted shortly regarding using year intervals with dates.
N years
ADD_MONTHS(DATE,12*n) DATE + NUMTOYMINTERVAL(n,'year')
In general, when using the Oracle DATE type, I recommend the following: Use the NUMTODSINTERVAL built-in function to add hours, minutes, and seconds. Add a simple number to add days. Use the ADD_MONTHS built-in function to add months and years.
I do not recommend using the NUMTOYMINTERVAL function. The reason has to do with how the functions behave at the months end. The ADD_MONTHS function treats the end of month days specially. It will, in effect, round the dates for us if we add one month to a month that has 31 days and the next month has fewer than 31 days, ADD_MONTHS will return the last day of the next month. Additionally, adding one month to the last day of a month results in the last day of the next month. We see this when adding one month to a month with 30 or fewer days: ops$tkyte@ORA11GR2> alter session set nls_date_format = 'dd-mon-yyyy hh24:mi:ss'; Session altered. ops$tkyte@ORA11GR2> select dt, add_months(dt,1) 2 from (select to_date('29-feb-2000','dd-mon-yyyy') dt from dual ) 3 / DT ADD_MONTHS(DT,1) -------------------- -------------------29-feb-2000 00:00:00 31-mar-2000 00:00:00 ops$tkyte@ORA11GR2> select dt, add_months(dt,1) 2 from (select to_date('28-feb-2001','dd-mon-yyyy') dt from dual ) 3 / DT ADD_MONTHS(DT,1) -------------------- -------------------28-feb-2001 00:00:00 31-mar-2001 00:00:00 ops$tkyte@ORA11GR2> select dt, add_months(dt,1) 2 from (select to_date('30-jan-2001','dd-mon-yyyy') dt from dual ) 3 / DT ADD_MONTHS(DT,1) -------------------- -------------------30-jan-2001 00:00:00 28-feb-2001 00:00:00
CHAPTER 12 DATATYPES
ops$tkyte@ORA11GR2> select dt, add_months(dt,1) 2 from (select to_date('30-jan-2000','dd-mon-yyyy') dt from dual ) 3 / DT ADD_MONTHS(DT,1) -------------------- -------------------30-jan-2000 00:00:00 29-feb-2000 00:00:00 See how the result of adding one month to February 29, 2000, results in March 31, 2000 February 29 was the last day of that month so ADD_MONTHS returned the last day of the next month. Additionally, notice how adding one month to January 30, 2000 and 2001 results in the last day of February 2000 and 2001, respectively. If we compare this to how adding an interval would work, we see very different results: ops$tkyte@ORA11GR2> select dt, dt+numtoyminterval(1,'month') 2 from (select to_date('29-feb-2000','dd-mon-yyyy') dt from dual ) 3 / DT DT+NUMTOYMINTERVAL(1 -------------------- -------------------29-feb-2000 00:00:00 29-mar-2000 00:00:00 ops$tkyte@ORA11GR2> select dt, dt+numtoyminterval(1,'month') 2 from (select to_date('28-feb-2001','dd-mon-yyyy') dt from dual ) 3 / DT DT+NUMTOYMINTERVAL(1 -------------------- -------------------28-feb-2001 00:00:00 28-mar-2001 00:00:00 Notice how the resulting date is not the last day of the next month, but rather the same day of the next month. It is arguable that this behavior is acceptable, but consider what happens when the resulting month doesn t have that many days: ops$tkyte@ORA11GR2> select dt, dt+numtoyminterval(1,'month') 2 from (select to_date('30-jan-2001','dd-mon-yyyy') dt from dual ) 3 / select dt, dt+numtoyminterval(1,'month') * ERROR at line 1: ORA-01839: date not valid for month specified ops$tkyte@ORA11GR2> select dt, dt+numtoyminterval(1,'month') 2 from (select to_date('30-jan-2000','dd-mon-yyyy') dt from dual ) 3 / select dt, dt+numtoyminterval(1,'month') * ERROR at line 1: ORA-01839: date not valid for month specified In my experience, this makes using a month interval in date arithmetic impossible in general. A similar issue arises with a year interval: adding one year to February 29, 2000, results in a runtime error because there is no February 29, 2001.
CHAPTER 12 DATATYPES
Getting the Difference Between Two DATEs
Another frequently asked question is, How do I retrieve the difference between two dates The answer is deceptively simple: you just subtract them. This will return a number representing the number of days between the two dates. Additionally, you have the built-in function MONTHS_BETWEEN that will return a number representing the number of months including fractional months between two dates. Lastly, with the INTERVAL types, you have yet another method to see the elapsed time between two dates. The following SQL query demonstrates the outcome of subtracting two dates (showing the number of days between them), using the MONTHS_BETWEEN function and then the two functions used with INTERVAL types: ops$tkyte%ORA11GR2> select dt2-dt1 , 2 months_between(dt2,dt1) months_btwn, 3 numtodsinterval(dt2-dt1,'day') days, 4 numtoyminterval(trunc(months_between(dt2,dt1)),'month') months 5 from (select to_date('29-feb-2000 01:02:03','dd-mon-yyyy hh24:mi:ss') dt1, 6 to_date('15-mar-2001 11:22:33','dd-mon-yyyy hh24:mi:ss') dt2 7 from dual ) 8 / DT2-DT1 MONTHS_BTWN DAYS MONTHS ---------- ----------- ------------------------------ ------------380.430903 12.5622872 +000000380 10:20:30.000000000 +000000001-00 Those are all correct values, but not of great use to us yet. Most applications would like to display the years, months, days, hours, minutes, and seconds between the dates. Using a combination of the preceding functions, we can achieve that goal. We ll select out two intervals: one for the years and months, and the other for just the day, hours, and so on. We ll use the MONTHS_BETWEEN built-in function to determine the decimal number of months between the two dates, and then we ll use the NUMTOYMINTERVAL built-in function to convert that number into the years and months. Additionally, we ll use MONTHS_BETWEEN to subtract the integer number of months between the two dates from the larger of the two dates to get down to the days and hours between them: ops$tkyte%ORA11GR2> select numtoyminterval 2 (trunc(months_between(dt2,dt1)),'month') 3 years_months, 4 numtodsinterval 5 (dt2-add_months( dt1, trunc(months_between(dt2,dt1)) ), 6 'day' ) 7 days_hours 8 from (select to_date('29-feb-2000 01:02:03','dd-mon-yyyy hh24:mi:ss') dt1, 9 to_date('15-mar-2001 11:22:33','dd-mon-yyyy hh24:mi:ss') dt2 10 from dual ) 11 / YEARS_MONTHS DAYS_HOURS --------------- -----------------------------+000000001-00 +000000015 10:20:30.000000000 Now it is clear that there is 1 year, 15 days, 10 hours, 20 minutes, and 30 seconds between the two DATEs.
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