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CHAPTER 14 THE 10053 TRACE FILE
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SORT resource Sort statistics Sort width: 58 Area size: 208896 Max Area size: Degree: 1 Blocks to Sort: 1 Row size: 31 Total Rows: Initial runs: 1 Merge passes: 0 IO Cost / pass: Total IO sort cost: 0 Total CPU sort cost: 5094402 Total Temp space used: 0 SORT resource Sort statistics Sort width: 58 Area size: 208896 Max Area size: Degree: 1 Blocks to Sort: 1 Row size: 36 Total Rows: Initial runs: 1 Merge passes: 0 IO Cost / pass: Total IO sort cost: 0 Total CPU sort cost: 5033608 Total Temp space used: 0 Merge join Cost: 194 Resp: 194
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Then we do the calculation for the second possibility on the merge join the one that uses the primary key index to avoid a sort. Because the first data set is going to be presorted when it arrives, we see only one section labeled SORT resource. Unfortunately, it turns out to be a waste of effort, as it is a more expensive strategy than not using the index. Despite comments in the documentation, if Oracle were able to acquire the second set of data in sorted order, it would still sort it I think this is to cater to the general case where the join condition is not a test for equality and the second set of data has to be instantiated so that a range-based join can keep resetting its start position in the second data set. SM Join (with index on outer) Access Path: index (no start/stop keys) Index: GGP_PK rsc_cpu: 2266849 rsc_io: 253 ix_sel: 1.0000e+000 ix_sel_with_filters: 1.0000e+000 Outer table: resc: 253 cdn: 261 rcz: 19 deg: 1 resp: 253 Inner table: GRANDPARENT Alias: GP resc: 128 cdn: 110 rcz: 23 deg: 1 resp: 128 using join:1 distribution:2 #groups:1 SORT resource Sort statistics Sort width: 58 Area size: 208896 Max Area size: Degree: 1 Blocks to Sort: 1 Row size: 36 Total Rows: Initial runs: 1 Merge passes: 0 IO Cost / pass: Total IO sort cost: 0 Total CPU sort cost: 5033608 Total Temp space used: 0 Merge join Cost: 382 Resp: 382
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HA Join Outer table: resc: 64 cdn: 261 rcz: 19 deg: 1 resp: 64 Inner table: GRANDPARENT Alias: GP resc: 128 cdn: 110 rcz: 23 deg: 1 resp: 128 using join:8 distribution:2 #groups:1 Hash join one ptn Resc: 1 Deg: 1 hash_area: 124 (max=2560) buildfrag: 1 probefrag: 1 ppasses: 1 Hash join Resc: 193 Resp: 193 Join result: cost: 193 cdn: 110 rcz: 42 Now joining: CHILD[C]#0 ******* NL Join Outer table: cost: 193 cdn: 110 rcz: 42 resp: 193 Inner table: CHILD Alias: C Access Path: table-scan Resc: 2517 Join: Resc: 277050 Resp: 277050 Best NL cost: 277050 resp: 277050 Join Card: 7476.42 = outer (109.94) * inner (68.01) * sel (1.0000e+000) ***********************
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Join order[18]
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Our final join order reuses the partial result for (greatgrandparent, grandparent) from Join order [17], and stops on the third table. Join order[18]: GREATGRANDPARENT[GGP]#3 GRANDPARENT[GP]#2 PARENT[P]#1 CHILD[C]#0 Now joining: PARENT[P]#1 ******* NL Join Outer table: cost: 193 cdn: 110 rcz: 42 resp: 193 Inner table: PARENT Alias: P Access Path: table-scan Resc: 629 Join: Resc: 69403 Resp: 69403 Access Path: index (scan) Index: P_PK rsc_cpu: 15523 rsc_io: 2 ix_sel: 5.0000e-007 ix_sel_with_filters: 5.0000e-007 NL Join: resc: 413 resp: 413 Best NL cost: 413 resp: 413 Using concatenated index cardinality for table GRANDPARENT Revised join selectivity: 5.0000e-004 = 8.3417e-005 * (1/2000) * (1/8.3417e-005) Join Card: 6.05 = outer (109.94) * inner (110.05) * sel (5.0000e-004)
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CHAPTER 14 THE 10053 TRACE FILE
SM Join Outer table: resc: 193 cdn: 110 rcz: 42 deg: 1 resp: 193 Inner table: PARENT Alias: P resc: 631 cdn: 110 rcz: 27 deg: 1 resp: 631 using join:1 distribution:2 #groups:1 SORT resource Sort statistics Sort width: 58 Area size: 208896 Max Area size: Degree: 1 Blocks to Sort: 1 Row size: 57 Total Rows: Initial runs: 1 Merge passes: 0 IO Cost / pass: Total IO sort cost: 0 Total CPU sort cost: 5033608 Total Temp space used: 0 SORT resource Sort statistics Sort width: 58 Area size: 208896 Max Area size: Degree: 1 Blocks to Sort: 1 Row size: 40 Total Rows: Initial runs: 1 Merge passes: 0 IO Cost / pass: Total IO sort cost: 0 Total CPU sort cost: 5033608 Total Temp space used: 0 Merge join Cost: 826 Resp: 826 HA Join Outer table: resc: 193 cdn: 110 rcz: 42 deg: 1 resp: 193 Inner table: PARENT Alias: P resc: 631 cdn: 110 rcz: 27 deg: 1 resp: 631 using join:8 distribution:2 #groups:1 Hash join one ptn Resc: 1 Deg: 1 hash_area: 124 (max=2560) buildfrag: 1 probefrag: 1 ppasses: 1 Hash join Resc: 824 Resp: 824
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The next two lines appeared in 10g. I don t understand the significance of the (newjo-stop-1), although the permutation count (perm:)of 18 and the maximum permutation (maxperm:) of 2,000 are references to the permutations we saw and the parameter _optimizer_max_permutations respectively. The (newjo-save) line simply lists the join order that was finally chosen by quoting the table numbers in order, using the numbers given to the tables in the first join order. (newjo-stop-1) k:0, spcnt:0, perm:18, maxperm:2000 (newjo-save) [2 1 0 3 ] Finally, we have got to the end of the work, and Oracle reports the join order that gave us the best plan. (This is a luxury introduced by 10g and only back-ported to the later versions of 9i. In earlier versions you had to read backwards up the file to the last appearance of Best so far:.) The final cost is also reported here, broken down into its I/O and CPU components. As we have done earlier in the file, we can divide the quoted CPU cost by 5,000,000 to find the value to add to the I/O cost to get the overall cost.
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