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CHAPTER 13 TRIGGERS
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FROM DELETED d JOIN TransactionDetails.TransactionTypes tt ON tt.TransactionTypeId = d.TransactionType WHERE AffectCashBalance = 1),0) FROM CustomerDetails.Customers c JOIN DELETED d ON d.CustomerId = c.CustomerId UPDATE CustomerDetails.Customers SET ClearedBalance = ClearedBalance + ISNULL((SELECT CASE WHEN CreditType = 0 THEN i.Amount * -1 ELSE i.Amount END FROM INSERTED i JOIN TransactionDetails.TransactionTypes tt ON tt.TransactionTypeId = i.TransactionType WHERE AffectCashBalance = 1),0) FROM CustomerDetails.Customers c JOIN INSERTED i ON i.CustomerId = c.CustomerId RAISERROR ('We have completed an update',10,1) END ELSE RAISERROR ('Updates have been skipped',10,1) 8. We can now test out the example, which will not update the Amount or TransactionType but will alter the DateEntered. SELECT FROM WHERE SELECT FROM WHERE UPDATE SET WHERE SELECT FROM WHERE SELECT FROM WHERE * TransactionDetails.Transactions TransactionId=5 ClearedBalance CustomerDetails.Customers CustomerId = 1 TransactionDetails.Transactions DateEntered = DATEADD(dd,-1,DateEntered) TransactionId = 5 * TransactionDetails.Transactions TransactionId=5 ClearedBalance CustomerDetails.Customers CustomerId = 1
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9. Once we have run this code, we will see the Results tab showing the DateEntered being altered but the ClearedBalance not, as Figure 13-6 illustrates. However, at this point we don t know if this is because we have removed and then readded the amount, giving a null effect.
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Figure 13-6. Details where updates have been skipped 10. Moving to the Messages tab, we can see the RAISERROR that occurred when we skipped updating the CustomerDetails.Customers table. There are also fewer row(s) affected messages. (1 row(s) affected) (1 row(s) affected) Updates have been skipped (1 row(s) affected) (1 row(s) affected) (1 row(s) affected) This brings us to the end of looking at the UPDATE() function. Let s move on to COLUMNS_UPDATED().
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Using COLUMNS_UPDATED()
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Instead of working with a named single column, the COLUMNS_UPDATED() function can work with multiple columns. It does this through the use of bit flags rather than naming columns. There are 8 bits in a byte, and a bit can be either off (a value of 0) or on (a value of 1). COLUMNS_UPDATED() checks the bits of a single byte, which is provided by SQL Server, to see whether a column has been updated. It can do this by correlating a bit with a column in the underlying table. So to clarify, the TransactionDetails.Transactions table has nine columns. The first column, TransactionId, would relate to the first bit within the byte. The Amount column is the fifth column and therefore would relate to the fifth bit within the byte. If the first bit is on (a value of 1), the TransactionId column has been updated. Similarly, if the fourth bit is on, the Amount column has been updated.
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Note Confusingly, when talking about bits, the first bit is known as bit 0, the second bit is known as bit 1, and the byte is made up of bits 0 through 7. Therefore, the TransactionId column is bit 0, and the Amount column is bit 4. We will use this convention from this point onwards.
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The bit flag settings are based on the column order of the table definition. To test for a bit value, you use the ampersand (&) operator to test a specific bit or multiple set of bits. Before we discuss how this works, inspect the following table. A bit value increases by the power of 2 as you progress down the bit settings, as you can see.
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0 1 2 3 4 5 6 7
Value
1 2 4 8 16 32 64 128
Note Another point about bits is that they work from right to left. For example, 00000010 shows bit 1 is
set and therefore a value of 2.
Now if bits 2 and 4 are switched on within a byte, in other words, they have a setting of true (00010100), then the value is 4 + 16, which equates to 20. Therefore, to test whether the third and fifth columns of our table have BOTH been altered, we would use the following syntax: IF COLUMNS_UPDATE() & 20 > 0 This is a great deal to take in and understand, so I have included the following code to help you to understand this further. Here we have a byte data type variable. We then set the variable to a value; in this case, we believe that bits 0 and 1 will be set. By using the & operator we can check this. To reiterate, slightly confusingly, it s not the bit position we have to test, but the corresponding bit value, so bit 0 has a value of 1. DECLARE @BitTest varbinary SET @BitTest = 3 SELECT @BitTest & 1,@BitTest & 2,@BitTest & 4,@BitTest & 8,@BitTest & 16 As a byte contains 8 bits, COLUMNS_UPDATED() can only test the first eight columns on this basis. Obviously, tables will contain more than eight columns, as you have seen with the TransactionDetails.Transaction table we have just been using. Once a table has more than eight columns, things change. Instead of being able to test COLUMNS_UPDATED() & 20 > 0 to check whether columns 3 or 5 have updated, it is necessary to SUBSTRING() the value first. Therefore, to test columns 3 or 5, the code needs to read as follows: IF (SUBSTRING(COLUMNS_UPDATED(),1,1) & 20) > 0
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