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APPENDIX B
Answers to the Exercises
This appendix provides answers and solutions to the chapter-ending exercises presented earlier in this book. In some cases, we have presented multiple (alternative) solutions for a single exercise. Sometimes you will see warnings for possible incorrect solutions, in case of known pitfalls. Of course, it is impossible to list all correct solutions for each exercise; the SQL language is too rich (or redundant ) for such an attempt. This implies that it is perfectly possible for you to approach and solve certain exercises in a completely different way. In that case, you can compare your results with the results listed in this appendix. However, always keep the following warning in mind.
Caution Although a query may produce the correct result, this doesn t imply that you wrote the right query. Incorrect SQL statements sometimes produce the correct results by accident. These are the most treacherous queries, because they can start producing wrong results at any point in the future, based on the actual contents of the tables involved.
Some exercises in this book are quite tough. For some of them, it may be challenging to fully appreciate and understand the given solutions. The reasoning behind including such exercises is the following: to test your SQL knowledge, you can look at the abundance of relatively simple examples in Oracle SQL Reference, and you can easily come up with simple SQL experiments yourself.
4 Exercises
1. Provide the code and description of all courses with an exact duration of four days. Solution 4-1. SQL> select code, description 2 from courses 3 where duration = 4;
APPENDIX B
ANSWERS TO THE EXERCISES
CODE ---SQL JAV GEN SQL>
DESCRIPTION -----------------------------Introduction to SQL Java for Oracle developers System generation
2. List all employees, sorted by job, and per job by age (from young to old). Solution 4-2. SQL> select * 2 from employees 3 order by job, bdate desc; EMPNO ----7900 7934 7839 7566 7782 7698 7844 7521 7499 7654 7876 7369 7788 7902 ENAME -------JONES MILLER KING JONES CLARK BLAKE TURNER WARD ALLEN MARTIN ADAMS SMITH SCOTT FORD INIT ----R TJA CC JM AB R JJ TF JAM P AA N SCJ MG JOB MGR BDATE MSAL COMM DEPTNO -------- ----- ----------- ----- ----- ------ADMIN 7698 03-DEC-1969 800 30 ADMIN 7782 23-JAN-1962 1300 10 DIRECTOR 17-NOV-1952 5000 10 MANAGER 7839 02-APR-1967 2975 20 MANAGER 7839 09-JUN-1965 2450 10 MANAGER 7839 01-NOV-1963 2850 30 SALESREP 7698 28-SEP-1968 1500 0 30 SALESREP 7698 22-FEB-1962 1250 500 30 SALESREP 7698 20-FEB-1961 1600 300 30 SALESREP 7698 28-SEP-1956 1250 1400 30 TRAINER 7788 30-DEC-1966 1100 20 TRAINER 7902 17-DEC-1965 800 20 TRAINER 7566 26-NOV-1959 3000 20 TRAINER 7566 13-FEB-1959 3000 20
14 rows selected. SQL> 3. Which courses have been held in Chicago and/or in Seattle Solution 4-3. SQL> select distinct course 2 from offerings 3 where location in ('CHICAGO','SEATTLE'); COURSE -----JAV OAU RSD
APPENDIX B
ANSWERS TO THE EXERCISES
SQL XML SQL> Notice the DISTINCT keyword in the SELECT clause, to ensure that a course code doesn t show up more than once. This way, you get the correct answer to the question. 4. Which employees attended both the Java course and the XML course (Provide their employee numbers.) Solution 4-4. SQL> 2 3 4 5 6 select from where and attendee registrations course = 'JAV' attendee in (select attendee from registrations where course = 'XML');
ATTENDEE -------7499 SQL> You might want to add the DISTINCT keyword to the SELECT clause here, too, just as you did in the previous exercise; otherwise, what happens if someone attends the XML course once and attends the Java course twice This fourth exercise has many different solutions. For example, you can also use two subqueries instead of one. Obviously, the following solutions with AND or OR at the row level are wrong: where course = 'JAV' and course = 'XML' where course = 'JAV' or course = 'XML' -- Wrong: Gives "no rows selected." -- Wrong: Gives too many results.
5. List the names and initials of all employees, except for R. Jones. Solution 4-5a. Using Parentheses SQL> select ename, init 2 from employees 3 where not (ename = 'JONES' and init = 'R'); ENAME -------SMITH ALLEN WARD JONES MARTIN INIT ----N JAM TF JM P
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