Working Days in .NET framework

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Working Days
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Calculating the number of working days between two given dates is quite a common request . Note that both inclusive and non-inclusive counts are useful . In inclusive counts, I m referring to taking into account the start and end dates of the range . I ll be demonstrating techniques to calculate an inclusive count . In cases for which you need to consider weekends,
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Inside Microsoft SQL Server 2008: T-SQL Programming
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holidays, and other special events as nonworking days, you might want to use an auxiliary table of dates . You mark each date as working or nonworking, and when requested to calculate the number of working days, you count the rows representing working days between the two given dates . You can even optimize the solution by keeping an attribute with a cumulative count of working days as of some base date . To calculate working days, simply retrieve the cumulative values of the given input dates and subtract one from another . However, when you want to consider only weekends as nonworking days, you don t need an auxiliary table at all . Instead, here s a solution for calculating the number of working days between @s and @e, which can be local variables or input arguments of a routine:
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DECLARE @s AS DATE = '20090101', @e AS DATE = '20091231'; SELECT days/7*5 + days%7 - CASE WHEN 6 BETWEEN - CASE WHEN 7 BETWEEN FROM (SELECT DATEDIFF(day, @s, DATEPART(weekday, ) AS D;
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wd AND wd + days%7-1 THEN 1 ELSE 0 END wd AND wd + days%7-1 THEN 1 ELSE 0 END @e) + 1 AS days, @s) AS wd
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The solution is very fast because it involves no I/O . The derived table query calculates the number of days (days) between @s and @e, inclusive of both @s and @e, and the weekday number (wd) of the date @s based on the login s language setting . Of course, if you wish, you can calculate the weekday number in a language-neutral manner using the aforementioned techniques . The outer query calculates the following: the number of working days in whole weeks covered by the range (days/7*5) plus the number of days in the partial week, if any (days%7), minus 1 if the partial week contains weekday 6 and minus 1 again if the partial week contains weekday 7 . For the given dates January 1, 2009, through December 31, 2009 you get 261 working days .
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Generating a Series of Dates
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You might need a series of all possible dates between two input dates . Such a series could be used, for example, to populate a time dimension in Analysis Services . An auxiliary table of numbers makes the solution quite simple . I provided the code to create and populate an auxiliary table of numbers in 2, User-Defined Functions . Here s the code to generate the series of dates:
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DECLARE @startdt AS DATE = '20090101', @enddt AS DATE = '20091231';
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10 Working with Date and Time
SELECT DATEADD(day, n - 1, @startdt) AS dt FROM dbo.Nums WHERE n <= DATEDIFF(day, @startdt, @enddt) + 1;
If you don t have a Nums table and are not allowed to create new tables, you can use one of the table-valued function implementations that I showed in Inside T-SQL Querying . For example, I presented the following user-defined function (UDF), which accepts the desired number of rows as input and returns a sequence of numbers accordingly:
IF OBJECT_ID('dbo.GetNums') IS NOT NULL DROP FUNCTION dbo.GetNums; GO CREATE FUNCTION dbo.GetNums(@n AS BIGINT) RETURNS TABLE AS RETURN WITH L0 AS(SELECT 1 AS c UNION ALL SELECT 1), L1 AS(SELECT 1 AS c FROM L0 AS A CROSS JOIN L0 AS B), L2 AS(SELECT 1 AS c FROM L1 AS A CROSS JOIN L1 AS B), L3 AS(SELECT 1 AS c FROM L2 AS A CROSS JOIN L2 AS B), L4 AS(SELECT 1 AS c FROM L3 AS A CROSS JOIN L3 AS B), L5 AS(SELECT 1 AS c FROM L4 AS A CROSS JOIN L4 AS B), Nums AS(SELECT ROW_NUMBER() OVER(ORDER BY (SELECT 0)) AS n FROM L5) SELECT TOP(@n) n FROM Nums ORDER BY n; GO
Once the function is created, you can use it just like you use the Nums table:
DECLARE @startdt AS DATE = '20090101', @enddt AS DATE = '20091231'; SELECT DATEADD(day, n - 1, @startdt) AS dt FROM dbo.GetNums(DATEDIFF(day, @startdt, @enddt) + 1) AS Nums;
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