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Archiving Database Data
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Lesson 2: Archiving by Using Partitions
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The most difficult aspect of archiving data from an operational system is devising a strategy to delete the archived data without affecting data availability. SQL Server 2005 provides a solution to this problem with table partitioning. This lesson explains the features of partitioning and how to use partitioning for a data archival strategy.
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After this lesson, you will be able to:
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Decide if partitioning is appropriate. Specify physical location of tables, including file groups and a partitioning scheme. Design filegroups for partitioning. Specify physical placement of indexes.
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Estimated lesson time: 90 minutes
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Partitioning Overview
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Table partitioning was introduced in SQL Server 2005 as a means to split large tables across multiple storage structures. Previously, objects were restricted to a single filegroup that could contain multiple files. However, the placement of data within a filegroup was still determined by SQL Server. Table partitioning enables tables, indexes, and indexed views to be created on multi ple filegroups while also enabling the database administrator (DBA) to specify which portion of the object will be stored on a specific filegroup. The process for partitioning a table, index, or indexed view is as follows: 1. Create a partition function. 2. Create a partition scheme mapped to a partition function. 3. Create the table, index, or indexed view on the partition scheme.
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Exam Tip You can partition an existing object after it has been populated with data. To partition an existing table, you need to drop the clustered index and re-create the clustered index on the partition scheme. To partition an existing index or indexed view, drop the index and re-create the index on a partition scheme. You will want to be careful when partitioning existing objects that already contain data because doing so will cause a significant amount of disk input/output (I/O).
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Figure 14-1 shows an example of a basic partitioned table.
Lesson 2: Archiving by Using Partitions
Table ID 1 2 3 4 5 6 7 c1 c2 c3 c4 3 5 2 1 5 5 2 A B B L Y A F
Part. Function
Part. Scheme
3 5 2 1 5 5 2
Filegroup1 Filegroup2 Filegroup1 Filegroup4 Filegroup2 Filegroup2 Filegroup1
Figure 14-1 Partitioned table
Partition Functions
A partition function defines the boundary points that SQL Server uses to split data across a partition scheme. An example of a partition function is the following:
CREATE PARTITION FUNCTION
mypartfunction (int)
AS RANGE LEFT
FOR VALUES (10,20,30,40,50,60)
Each partition function requires a name and data type. The data type defines the lim its of the boundary points that can be applied and must span the same data range or less than the data type of a column in a table, index, or indexed view that the partition function is applied to. The data type for a partition function can be any native SQL Server data type; com mon language runtime (CLR) data types are not allowed except text, ntext, image, var binary(max), timestamp, xml, and varchar(max). Imprecise data types such as real must be persisted. Any columns that are used to partition must be deterministic. The AS clause enables you to specify whether the partition function you are creating is RANGE LEFT or RANGE RIGHT. The LEFT and RIGHT parameters define which partition will include a boundary point. You use the FOR VALUES clause to specify the boundary points for the partition func tion. If you create the partition function as RANGE LEFT, the boundary point is included in the left partition. If you create the partition function as RANGE RIGHT, the boundary point is included in the right partition. A partition function always maps the entire range of data, so no gaps are present. You cannot specify duplicate boundary points, which ensures that any value stored in a
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Archiving Database Data
column always evaluates to a single partition. Null values are always stored in the leftmost partition until you explicitly specify null as a boundary point and use the RANGE RIGHT syntax. In that case, nulls are stored in the rightmost partition. Because the entire range of values is always mapped for a partition function, the result is the creation of one more partition than you have defined boundary points. Table 14-1 shows how the following partition function is defined in SQL Server.
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