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Lesson Summary
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A partition scheme maps a partition function to a physical storage structure. Any object that uses the partition function will store its data within the associated partition scheme.
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Lesson 2: Creating a Partition Scheme
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Lesson Review
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The following questions are intended to reinforce key information presented in this lesson. The questions are also available on the companion CD if you prefer to review them in electronic form.
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NOTE
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Answers
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Answers to these questions and explanations of why each answer choice is right or wrong are located in the Answers section at the end of the book.
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What does a partition scheme define A. Boundary points for a partition B. Physical storage for a partition C. A rowset that returns the values in a partition D. The number of the partition containing a specified value
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6
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Creating Partitions
Lesson 3: Partitioning Tables and Indexes
After you create a partition function and a partition scheme, you are ready to partition a table, index, or indexed view. In this lesson, you learn how to partition a table as you create the table, how to partition an index as you create the index, and how to partition an existing table or index.
After this lesson, you will be able to:
Specify a partition scheme when creating a table. Specify a partition scheme when creating an index.
Estimated lesson time: 20 minutes
Creating a Partitioned Table, Index, or Indexed View
To create a partitioned table or index, you use the same syntax as when you create a regular table or index. Partitioning an indexed view is simply a matter of partitioning the index for the view. The general syntax of the CREATE TABLE Transact-SQL command is as follows:
CREATE TABLE [ database_name . [ schema_name ] . | schema_name . ] table_name ( { <column_definition> | <computed_column_definition> } [ <table_constraint> ] [ ,...n ] ) [ ON { partition_scheme_name ( partition_column_name ) | filegroup | "default" } ] [ { TEXTIMAGE_ON { filegroup | "default" } ] [ ; ]
The general syntax of the CREATE INDEX Transact-SQL command is as follows:
CREATE [ UNIQUE ] [ CLUSTERED | NONCLUSTERED ] INDEX index_name ON <object> ( column [ ASC | DESC ] [ ,...n ] ) [ INCLUDE ( column_name [ ,...n ] ) ] [ WITH ( <relational_index_option> [ ,...n ] ) ] [ ON { partition_scheme_name ( column_name ) | filegroup_name | default } ][ ; ]
The important partition-related clause in each command is the ON clause. To partition a table or index, instead of specifying a filegroup for the ON clause, you specify a partition scheme. The following code example shows the CREATE PARTITION FUNCTION, CREATE PARTITION SCHEME, and CREATE TABLE statements you would use to partition the CustomerAddress table:
CREATE PARTITION FUNCTION partfunc (int) AS RANGE LEFT FOR VALUES (1000, 2000, 3000, 4000, 5000);
Lesson 3: Partitioning Tables and Indexes
GO CREATE PARTITION SCHEME partscheme AS PARTITION partfunc TO ([FG1], [FG2], [FG3], [FG4], [FG5], [FG6]) GO CREATE TABLE dbo.CustomerAddress (CustomerAddressID int AddressTypeID tinyint PrimaryAddressFlag bit AddressLine1 varchar(30) AddressLine2 varchar(30) AddressLine3 varchar(30) City varchar(50) StateProvinceID int PostalCode char(10) CountryID int ON partscheme(CustomerAddressID);
IDENTITY(1,1) PRIMARY KEY CLUSTERED, NOT NULL, NOT NULL, NOT NULL, NULL, NULL, NOT NULL, NULL, NULL, NULL)
This example does the following:
Creates a partition function called partfunc Creates a partition scheme called partscheme Creates the dbo.CustomerAddress table with the specified definition Stores the table on the partition scheme partscheme Uses the CustomerAddressID column in the table to determine which rows in the table belong within a given partition
As data is added to the table, any rows with a CustomerAddressID of 1,000 or less will fall into Partition 1 and be stored on FG1, addresses with an ID of 1,001 to 2,000 will fall into Partition 2 and be stored on FG2, and so on.
Partitioned Indexes and Included Columns
The following example shows how to create a partitioned index on the same table:
CREATE NONCLUSTERED INDEX idx_CustomerAddress_City ON dbo.CustomerAddress(City) ON partscheme(CustomerAddressID);
The interesting piece of syntax here is that the index is defined on the City column. However, the index is partitioned by the CustomerAddressID column, which does not exist in the index definition. Partitioning takes advantage of the included columns feature that 4, Creating Indexes, discusses. With the included columns feature, any columns that make up the clustered index are automatically migrated into any index created against the table. This lets you partition the indexes
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