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Lesson 3
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1. Correct Answers: B and C A. Incorrect: Interfaces define a contract between types; inheritance derives a type from a base type. B. Correct: Interfaces define a contract between types, ensuring that a class implements specific members. C. Correct: Inheritance derives a type from a base type, automatically implementing all members of the base class, while allowing the derived class to extend or override the existing functionality. D. Incorrect: Interfaces define a contract between types; inheritance derives a type from a base type. 2. Correct Answers: A and C A. Correct: Nullable is a generic type. B. Incorrect: Boolean is a nongeneric value type. C. Correct: EventHandler is a generic type. D. Incorrect: System.Drawing.Point is a structure and is not generic.
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Answers
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Correct Answer: D A. Incorrect: The Object class does not have a Dispose member method. Additionally, you would need to use a constraint to mandate types implementing the IDisposable interface to call the Dispose method. B. Incorrect: Implementing an interface does not enable generic types to use interface methods. C. Incorrect: Deriving the generic class from an interface does not enable generic types to use interface methods. D. Correct: If you use constraints to require types to implement a specific interface, you can call any methods used in the interface.
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Correct Answer: A A. Correct: Delegates define the signature (arguments and return type) for the entry point. B. Incorrect: Event procedures can be Shared/static or instance members. C. Incorrect: If you mistyped the event procedure name, you would receive a different compiler error. D. Incorrect: Events work equally well, regardless of the language used.
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Lesson 4
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1. Correct Answer: A A. Correct: The primary reason to avoid boxing is because it adds overhead. B. Incorrect: Boxing requires no special privileges. C. Incorrect: Boxing does not make code less readable. 2. Correct Answers: A and B A. Correct: Value types are boxed when an abstract method inherited from System.Object is called. Overriding the method avoids boxing. B. Correct: By default, the ToString method simply returns the type name, which is typically not useful for a consuming application. C. Incorrect: The compiler does not require structures to override the ToString method. D. Incorrect: ToString never causes a run-time error; it simply returns the type name unless overridden.
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Answers
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Correct Answer: B A. Incorrect: You can t omit a member of an interface and still conform to that interface. B. Correct: InvalidCastException is the recommended exception to throw. C. Incorrect: While you could throw a custom exception, using standard exception types makes it easier for developers writing code to consume your type to catch specific exceptions. D. Incorrect: You must return a value for each conversion member.
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Correct Answers: A and C A. Correct: You can convert from Int16 to Int32 because that is considered a widening conversion. Because Int32 can store any value of Int16, implicit conversion is allowed. B. Incorrect: You cannot convert from Int32 to Int16 because that is considered a narrowing conversion. Because Int16 cannot store any value of Int32, implicit conversion is not allowed. C. Correct: You can convert from Int16 to Double because that is considered a widening conversion. Because Double can store any value of Int16, implicit conversion is allowed. D. Incorrect: You cannot convert from Double to Int16 because that is considered a narrowing conversion. Because Int16 cannot store any value of Double, implicit conversion is not allowed.
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1: Case Scenario Answers
Case Scenario: Designing an Application
1. Both subscribers and doctors will have a lot of information in common, including names, phone numbers, and addresses. However, they will each have unique information, also. For example, you need to track the subscription plan and payment information for subscribers. For doctors, you need to track contract details, medical certifications, and specialties. Therefore, you should create separate classes for subscribers and doctors, but derive them from a single class that contains all members shared by both classes. To do this, you could create a base class named Person, and derive both the Subscriber and Doctor classes from Person. 2. You can use an array to store a group of subscribers.
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