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A local var iable in T- SQL oper at es like a m em ory var iable in Visual Basic. Ch a pt e r 3 provides explicit coverage of T- SQL local variables.
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--ComputeWithDatediff --Demonstrates use of DATEDIFF function to compute --a difference in milliseconds. DECLARE @dtStart datetime DECLARE @dtEnd datetime DECLARE @intOrderID int SET @intOrderID = 10700 SET @dtStart = GETDATE() SELECT OrderID, Quantity, UnitPrice, Discount, CAST(Quantity*UnitPrice*(1Discount) AS money) AS Price as money , CAST(Quantity*UnitPrice*(1Discount) AS dec(9,2)) Price as dec(9,2) FROM [Order Details] WHERE OrderID < @intOrderID SET @dtEnd = GETDATE() SELECT DATEDIFF(ms, @dtStart, @dtEnd) Time to run (ms)
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T- SQL aggr egat e funct ions can apply t o all t he rows in a r esult set or j ust subset s of t hem , such as t hose ident ified w it h a GROUP BY clause. For exam ple, you can count t he num ber of ov erall rows in a r ow sour ce, or y ou can count t he rows by count ry ( or by any ot her value on which y ou gr oup r ows) . You can choose t o ret ur n aggr egat e values and t he r ows t hey sum m ar ize, or j ust t he aggr egat e values.
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Table 3- 1 it em izes t he aggregat e funct ions by list ing t heir nam es wit h a short descript ion. The purpose of m any of t hese funct ions is im plied by t heir nam e. For furt her det ails about funct ionalit y and synt ax , search Books Online for a t opic wit h t he funct ion nam e. 7DEOH  6XPPDU\ RI 764/ $JJUHJDWH )XQFWLRQV 'HVFULSWLRQ Ret urns an average Can ret urn t he binary check sum for a row Com put es a checksum for use in const ruct ing hash index es Count s t he it em s in a gr oup or ov erall row source; r et ur ns an int value Like Count funct ion but ret ur ns a bigint value For use wit h CUBE and ROLLUP operat ors Ret urns m axim um value in a colum n Ret urns m inim um value in a colum n Ret urns sum of values in a colum n 1DPH AVG BI NARY CHECKSUM CHECKSUM COUNT COUNT BI G GROUPI NG MAX MI N SUM
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CHECKSUM AGG Per form s a checksum com put at ion for a group
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Com put es st andard dev iat ion for t he sam ple of values in a colum n Com put es st andard dev iat ion for t he populat ion of values fr om which a colum n sam ples Com put es var iance for t he sam ple of v alues in a colum n Com put es var iance for t he populat ion of values from w hich a colum n sam ples
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Like som e of t he ot her aggregat e funct ions, t he COUNT funct ion has m ult iple for m s. For exam ple, COUNT(*) ret ur ns t he num ber of values in a row source, including null and duplicat e values. The WHERE clause can const rain t he range of rows ov er which COUNT(*) com put es a r esult . I n t he next sam ple, t he r ow source includes all cust om ers fr om a count ry st art ing w it h t he let t er B or C. Because t he Cust om ers t able in t he Nort hwind dat abase has a pr im ary key, t he r ow s are all unique. This SELECT st at em ent ret ur ns a scalar value of 14, w hich is t he num ber of rows in t he Cust om er s t able m eet ing t he cr it er ion expr ession in t he WHERE clause. Not ice t hat like an earlier sam ple in t his chapt er , t his code lim it s count ries t o t hose st art ing w it h t he let t er B or C but does so using LEFT and I N rat her t han SUBSTRI NG. You can use eit her m et hod, but t his one requir es a lit t le less t yping. --CountRows --Count all rows meeting a criterion. SELECT Count(*) FROM Customers WHERE LEFT(Country,1) IN ( B , C ) You can use t he COUNT funct ion t o r et ur n j ust t he num ber of non- null v alues wit hin a colum n by replacing t he ast er isk w it h t he nam e of a specific colum n. Any rows w it h null values for a specific colum n in t he row source for t he quer y w on t be t allied as part of t he ret ur n value for t he COUNT funct ion. Changing t he ast erisk t o a specific colum n nam e Count ry won t change t he result in t he prev ious sam ple because t here aren t any null v alues in t he Count ry colum n. But you can change t he r esult by using t he DI STI NCT k eyw ord as a pr edicat e t o t he specific colum n. Posit ion t he k ey word inside t he par ent heses t railing t he funct ion. The follow ing scr ipt illust rat es t his synt ax. The query st at em ent r et ur ns t he value 3 because t her e are only t hree dist inct count r ies in t he Cust om ers t able st art ing wit h t he let t er B or C Belgium , Brazil, and Canada. --CountIncidences --Count distinct incidences. SELECT Count(DISTINCT Country) FROM Customers WHERE LEFT(Country,1) IN ( B , C )
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