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FAVOR PLAN DO NOT FAVOR PLAN in C#.NET
FAVOR PLAN DO NOT FAVOR PLAN PDF417 Decoder In C#.NET Using Barcode recognizer for .NET framework Control to read, scan PDF417 image in .NET applications. www.OnBarcode.comScan PDF 417 In C# Using Barcode reader for Visual Studio .NET Control to read, scan read, scan image in .NET framework applications. www.OnBarcode.comTenured Nontenured
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PDF417 2d Barcode Reader In C# Using Barcode scanner for .NET Control to read, scan PDF 417 image in .NET applications. www.OnBarcode.comEAN 13 Scanner In Visual C# Using Barcode reader for .NET framework Control to read, scan EAN / UCC  13 image in .NET framework applications. www.OnBarcode.comsolution: I Let p1 = the proportion of tenured faculty who favor the plan and let p2 = the proportion of nontenured faculty who favor the plan H0: p1 = p2 HA: p1 p2 II We will use a chisquare test for homogeneity of proportions The samples of tenured and nontenured instructors are given as random We determine that the expected values are given by the matrix 1278 1222 Because all expected values are 1022 978 greater than 5, the conditions for the test are present III X 2 = 178, df = (2 1)(2 1) = 1 015 < Pvalue < 020 (from Table C; on the TI83/84: P = 2 cdf(178,1000,1) = 0182) IV The Pvalue is not small enough to reject the null hypothesis These data do not provide strong statistical evidence that tenured and nontenured faculty differ in their attitudes toward the proposed salary plan X 2 = z2 The example just completed could have been done as a twoproportion ztest where p1 and p2 are defined the same way as in the example (that is, the proportions of tenured and nontenured staff that favor the new plan) Then 15 p1 = 25 and 8 p2 = 20 Computation of the ztest statistics for the twoproportion ztest yields z = 1333 Now, z2 = 178 Because the chisquare test and the twoproportion ztest are testing the same thing, it should come as little surprise that z2 equals the obtained value of X 2 in the example For a 2 2 table, the X 2 test statistic and the value of z2 obtained for the same data in a twoproportion ztest are the same Note that the ztest is somewhat more flexible in this case in that it allows for the possibility of a onesided test, whereas the chisquare test is strictly two sided (that is, it is simply a rejection of H0) However, this advantage only holds for a 2 2 table since there is no way to use a simple ztest for situations with more than two rows and two columns Digression: You aren t required to know these, but you might be interested in the following (unexpected) facts about a 2 distribution with k degrees of freedom: Recognizing ITF14 In Visual C# Using Barcode scanner for VS .NET Control to read, scan Case Code image in VS .NET applications. www.OnBarcode.comBar Code Decoder In ObjectiveC Using Barcode reader for iPhone Control to read, scan barcode image in iPhone applications. www.OnBarcode.comG G G G
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1 A study yields a chisquare statistic value of 20 (X 2 = 20) What is the Pvalue of the test if a the study was a goodnessoffit test with n = 12 b the study was a test of independence between two categorical variables, the row variable with 3 values and the column variable with 4 values Answer: a n = 12 df = 12 1 = 11 0025 < P < 005 (Using the TI83/84: 2cdf (20,1000,11) = 0045) b r = 3, c = 4 df = (3 1)(4 1) = 6 00025 < P < 0005 (Using the TI83/84: 2 cdf(20,1000,6) = 00028) 2 4 The following data were collected while conducting a chisquare test for independence: Preference BRAND A BRAND B BRAND C
Male Female
16 18 (X) 22 30 15 28 2 What null and alternative hypotheses are being tested Answer: H0: Gender and Preference are independent (or: H0: Gender and Preference are not related) HA: Gender and Preference are not independent (HA: Gender and Preference are related) 3 What is the expected value of the cell marked with the X Answer: Identifying the marginals on the table we have 16 18 (X) 34 22 30 52 15 28 43 53 76 129 Since there are 34 values in the column with the X, we expect to find 34 of each row 129 total in the cells of the first column Hence, the expected value for the cell containing 34 X is (76) = 2003 129 4 How many degrees of freedom are involved in the test Answer: df = (2 1)(3 1) = 2

