qr code reader camera c# Figure 5-1 Four State Truth Table in Visual C#.NET

Decoding QR Code in Visual C#.NET Figure 5-1 Four State Truth Table

Figure 5-1 Four State Truth Table
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Z Z L H X Z L H X
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L L L X X
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H H X H X
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X X X X X
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Subprograms and Packages
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Using all of this information, a designer can write a resolution function for this type The resolution function maintains the highest strength seen so far and compares this value with new values a single element at a time, until all values have been exhausted This algorithm returns the higheststrength value Following is an example of such a resolution function:
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PACKAGE fourpack IS TYPE fourval IS (X, L, H, Z); TYPE fourval_vector IS ARRAY (natural RANGE <> ) OF fourval; FUNCTION resolve( s: fourval_vector) RETURN fourval; END fourpack; PACKAGE BODY fourpack IS FUNCTION resolve( s: fourval_vector) RETURN fourval IS VARIABLE result : fourval := Z; BEGIN FOR i IN s RANGE LOOP CASE result IS WHEN Z => CASE s(i) IS WHEN H => result := H; WHEN L => result := L; WHEN X => result := X; WHEN OTHERS => NULL; END CASE; WHEN L => CASE s(i) IS WHEN H => result := X; WHEN X => result := X; WHEN OTHERS => NULL; END CASE; WHEN H => CASE s(i) IS WHEN L => result := X; WHEN X => result := X; WHEN OTHERS =>
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NULL; END CASE; WHEN X => result := X; END CASE; END LOOP; RETURN result; END resolve; END fourpack;
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Five
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The input argument is an unconstrained array of the driver-base type, fourval The resolution function examines all of the values of the drivers passed in argument s one at a time and returns a single value of fourval type to be scheduled as the signal value Variable result is initialized to a Z value to take care of the case of zero drivers for the signal In this case, the loop is never executed, and the result value returned is the initialization value It is also a good idea to initialize the result value to the weakest value of the value system to allow overwriting by stronger values If a nonzero number of drivers exists for the signal being resolved, then the loop is executed once for each driver value passed in argument s Each driver value is compared with the current value stored in variable result If the new value is stronger according to the rules outlined earlier, then the current result is updated with the new value Let s look at some example driver values to see how this works Assuming that argument s contained the driver values shown in Figure 5-2, what would the result be
Initial
Figure 5-2 Four State Resolution with Two Values
Value
Driver Values
Resultant Value
Subprograms and Packages
Because there are two drivers, the loop is executed twice The first time through, the loop variable result contains the initial value Z The first driver value is also a Z value Value Z compared with value Z produces a resulting value Z The next iteration through the loop retrieves the next driver value, which is H The value H compared with value Z returns value H The function therefore returns the value H as the resolved value of the signal Another case is shown in Figure 5-3 In this example, there are three drivers, and the resolution function executes the loop three times In the first iteration of the loop, the initial value of result (Z) is compared with the first driver value (H) The value H is assigned to result In the next iteration, result (H) is compared with the second driver (Z) The value H remains in result because the value Z is weaker Finally, the last iteration result (H) is compared with the last driver value (L) Because these values are of the same strength, the value X is assigned to result The value X is returned from the function as the resolved value for the signal NINE-VALUE RESOLUTION FUNCTION Some simulators use more complex types to represent the value of a signal For instance, what might a resolution function look like for a nine-value system, typical of most workstation-based simulators in use currently Following are the nine values in the value system:
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