# A CO(g) + 2 H2(g) CH3OH(g) H = 91 kJ in C#.NET Reader DataMatrix in C#.NET A CO(g) + 2 H2(g) CH3OH(g) H = 91 kJ

16 A CO(g) + 2 H2(g) CH3OH(g) H = 91 kJ
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6 B The system is insulated and no work can be done on or by the system (rigid container); thus, the energy is constant At the melting point, some of the gallium will melt and some will freeze, the entropy change of these two processes cancel each other so there is no net entropy change 7 E The process is endothermic (the ammonium chloride is absorbing heat to cool the water) Endothermic processes are helped by higher temperatures Answers A and C, and possibly D would give an increase in temperature There is insufficient information about answer B 8 E The reaction showing the greatest increase in the number of moles of gas will show the greatest entropy increase If no gases are present, then the
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CH3OH(g) CH3OH(I) CO(g) + 2 H2(g) CH3OH(l)
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H = 37 kJ H = 128 kJ
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17 B Dissolving almost always has: S > 0 A decrease in temperature means the process has: H > 0
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U Free-Response Questions
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Answer the following questions You have 10 minutes, and you may not use a calculator You may use the tables at the back of the book Xe(g) + 3F2 (g) XeF6(g)
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Under standard conditions, the enthalpy change for the reaction going from left to right (forward reaction) is: H = 294 kJ
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Thermodynamics 135
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