A CO(g) + 2 H2(g) CH3OH(g) H = 91 kJ in C#.NET

Reader DataMatrix in C#.NET A CO(g) + 2 H2(g) CH3OH(g) H = 91 kJ

16 A CO(g) + 2 H2(g) CH3OH(g) H = 91 kJ
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6 B The system is insulated and no work can be done on or by the system (rigid container); thus, the energy is constant At the melting point, some of the gallium will melt and some will freeze, the entropy change of these two processes cancel each other so there is no net entropy change 7 E The process is endothermic (the ammonium chloride is absorbing heat to cool the water) Endothermic processes are helped by higher temperatures Answers A and C, and possibly D would give an increase in temperature There is insufficient information about answer B 8 E The reaction showing the greatest increase in the number of moles of gas will show the greatest entropy increase If no gases are present, then the
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CH3OH(g) CH3OH(I) CO(g) + 2 H2(g) CH3OH(l)
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H = 37 kJ H = 128 kJ
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17 B Dissolving almost always has: S > 0 A decrease in temperature means the process has: H > 0
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U Free-Response Questions
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Answer the following questions You have 10 minutes, and you may not use a calculator You may use the tables at the back of the book Xe(g) + 3F2 (g) XeF6(g)
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Under standard conditions, the enthalpy change for the reaction going from left to right (forward reaction) is: H = 294 kJ
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Thermodynamics 135
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a Is the value of S , for the above reaction, positive or negative Justify your conclusion b The above reaction is spontaneous under standard conditions Predict what will happen to G for this reaction as the temperature is increased Justify your prediction c Will the value of K remain the same, increase, or decrease as the temperature increases Justify your prediction d Show how the temperature at which the reaction changes from spontaneous to nonspontaneous can be predicted What additional information is needed
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U Answers and Explanations
a The value is negative Give yourself 1 point if you predicted this The decrease in the number of moles of gas, during the reaction, means there is a decrease in entropy Give yourself 1 point for discussing the number of moles of gas You may get this point even if you did not get the first point b Recalling: G = H T S The value of G will increase (become less negative) Give yourself 1 point for this answer if it is clearly stated that increasing means less negative In general, both H and S are relatively constant As the temperature increases, the value of the entropy term, T S, becomes more negative The negative sign in front or this term leads to a positive contribution The value of G will first become less negative (more positive), and eventually the value will be positive (no longer spontaneous) Give yourself 1 point for the G = H T S argument even if you did not get the first point c Recalling: G = RT ln K The value of K will decrease You get 1 point for this answer As the value of G increases (see part b) the value of K will decrease You get 1 point for using G = RT ln K in your discussion If you got the justification for part b wrong, and you used the same argument here, you will not be penalized twice You still get your point d Recalling: G = H T S Rearranging this equation to: T = ( G H)/ S will allow the temperature to be estimated This is worth 1 point To do the calculation, the value of S is needed Give yourself 1 point for this There is total of 8 points possible All of the mathematical relations presented in the answers are provided in the exam booklet Note that many students lose points on a question like this because their answers are too long Keep your answers short and to the point, even if it appears that you have multiple pages available
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