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Handling XML in Ajax
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So to get to the <party> element, you actually have to get to the text node s next sibling That means that the correct JavaScript is partyNode = partiesNodefirstChildnextSibling:
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< xml version="10" > <parties> xxxx<party type="winter"> <party_title>Snow Day</party_title> <party_number>63</party_number>
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Similarly, to get to the <party_title> element node, you d use partyNodefirstChild nextSibling to skip over the indentation whitespace text node:
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< xml version="10" > <parties> <party type="winter"> <party_title>Snow Day</party_title> <party_number>63</party_number>
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So you can use the nextSibling and previousSibling properties to navigate over whitespace text nodes, but it s a pain Here s what the displayGuest function turns into when you take into account the default whitespace handling in Firefox:
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function displayGuest(xmldoc) { var partiesNode, partyNode, peopleNode; var personNode, firstNameNode, lastNameNode, displayText; partiesNode = xmldocdocumentElement; partyNode = partiesNodefirstChildnextSibling; peopleNode = partyNodelastChildpreviousSibling; personNode = peopleNodefirstChildnextSibling nextSiblingnextSiblingnextSiblingnextSibling; firstNameNode = personNodefirstChildnextSibling; lastNameNode = firstNameNodenextSiblingnextSibling; displayText = "The third guest is: " + firstNameNodefirstChildnodeValue + ' ' + lastNameNodefirstChildnodeValue; var target = documentgetElementById("targetDiv"); targetinnerHTML=displayText; }
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This looks like a mess it s bad enough having to navigate from element to element, but now we have to navigate over text nodes as well Isn t there a better way
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There is a better way for example, you can strip out indentation whitespace before Firefox gets its hands on it To do that, we might write a JavaScript function named removeWhitespace, which is passed a JavaScript XML document object:
function removeWhitespace(xml) { }
We can set up a loop over all nodes in the XML document object by looping over all child nodes:
function removeWhitespace(xml) { var loopIndex; for (loopIndex = 0; loopIndex < xmlchildNodeslength; loopIndex++) { } } }
And we get the current node in the loop from the childNodes property, which holds an array of child nodes:
function removeWhitespace(xml) { var loopIndex; for (loopIndex = 0; loopIndex < xmlchildNodeslength; loopIndex++) { var currentNode = xmlchildNodes[loopIndex]; } }
6:
Handling XML in Ajax
If the current node is an element node, which we can check by seeing if its nodeType property equals 1 (see Table 6-1), it might have child nodes and we ve got to remove the whitespace from those child nodes as well, so we pass the current node to the removeWhitespace function again:
function removeWhitespace(xml) { var loopIndex; for (loopIndex = 0; loopIndex < xmlchildNodeslength; loopIndex++) { var currentNode = xmlchildNodes[loopIndex]; if (currentNodenodeType == 1) { removeWhitespace(currentNode); } } }
Ask the Expert
Q: A:
Is calling removeWhitespace from inside that function an unusual practice Calling a function from inside that function is called recursion, and JavaScript supports recursion It s a legal technique, and, as you can see, it s a powerful one In this case, we use recursion to be able to loop over all the nodes in an XML document, no matter what the structure of that document Fifteen nested levels of elements No problem removeWhitespace will handle it by operating at each level, and calling itself to handle the child nodes on the current node
Now that we ve eliminated element nodes, we have a candidate indentation whitespace node of the kind we want to remove How do we check if it s removable whitespace We can remove any text node that is pure whitespace that is, only spaces So how do we check if the current node is a text node that consists of only spaces Text nodes have the nodeType property value set to 3, so we want to check that for sure We can also use a regular expression to check if the text node contains all spaces Regular expressions let you test the contents of text strings, and JavaScript supports regular expressions with the string test method The regular expression we ll test against is ^\s+$,
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