 Home
 Products
 Integration
 Tutorial
 Barcode FAQ
 Purchase
 Company
how to make barcode in c#.net Are you confused in Software
Are you confused Painting QR Code In None Using Barcode generation for Software Control to generate, create QR Code image in Software applications. Quick Response Code Decoder In None Using Barcode decoder for Software Control to read, scan read, scan image in Software applications. If you can t see straightaway how these solutions are derived, Tables 126 through 1210 show how the equations can be solved, stepbystep Note that in the third and fifth original equations above (and in Tables 128 and 1210), we must not let a equal 0 Also, in the fourth solution equation (and in Table 129), we must never allow either a or b to equal 0 Quick Response Code Drawer In Visual C#.NET Using Barcode creation for Visual Studio .NET Control to generate, create Quick Response Code image in VS .NET applications. QR Code Creator In .NET Framework Using Barcode printer for ASP.NET Control to generate, create QR Code JIS X 0510 image in ASP.NET applications. Products and Ratios
Quick Response Code Encoder In VS .NET Using Barcode drawer for .NET framework Control to generate, create QR image in VS .NET applications. Print QR Code ISO/IEC18004 In Visual Basic .NET Using Barcode maker for .NET Control to generate, create Quick Response Code image in .NET applications. Table 126 Paint EAN / UCC  13 In None Using Barcode generation for Software Control to generate, create UCC.EAN  128 image in Software applications. Printing Barcode In None Using Barcode generator for Software Control to generate, create bar code image in Software applications. Statements 4x = 0 4x /4 = 0/4 x=0
Code39 Maker In None Using Barcode creation for Software Control to generate, create Code 3/9 image in Software applications. UPC A Creator In None Using Barcode drawer for Software Control to generate, create UPC A image in Software applications. Process for solving the equation 4x = 0
EAN13 Maker In None Using Barcode creator for Software Control to generate, create EAN13 image in Software applications. Code 128 Creator In None Using Barcode encoder for Software Control to generate, create Code 128B image in Software applications. Reasons This is the equation we are given Divide each side through by 4 Simplify each side
International Standard Book Number Encoder In None Using Barcode generator for Software Control to generate, create ISBN image in Software applications. Print EAN128 In None Using Barcode creation for Office Excel Control to generate, create GTIN  128 image in Office Excel applications. Table 127 Recognize Barcode In Java Using Barcode decoder for Java Control to read, scan read, scan image in Java applications. Printing EAN13 In None Using Barcode generator for Font Control to generate, create EAN13 Supplement 5 image in Font applications. Statements x /7 = 2 7x /7 = 7 2 x = 14
Barcode Decoder In Visual Basic .NET Using Barcode reader for Visual Studio .NET Control to read, scan read, scan image in .NET applications. Barcode Creation In VB.NET Using Barcode maker for .NET Control to generate, create bar code image in VS .NET applications. Process for solving the equation x / 7 = 2 UPC A Maker In None Using Barcode creation for Font Control to generate, create UPC Symbol image in Font applications. Bar Code Drawer In Java Using Barcode encoder for Android Control to generate, create bar code image in Android applications. Reasons This is the equation we are given Multiply each side by 7 Simplify each side
Table 128 Statements 2x /a = b a(2x /a) = ab 2x = ab 2x /2 = ab /2 x = ab /2 Process for solving the equation 2x /a = b, provided a 0
Reasons This is the equation we are given Multiply each side by a Simplify the left side Divide each side by 2 Simplify the left side Table 129 Process for solving the equation 5abx = c, provided a 0 and b 0
Reasons This is the equation we are given We are about to divide through by the product of these constants This will allow us to solve the equation in a streamlined fashion Divide through by the constant (5ab) Simplify the left side Statements 5abx = c Require that a 0 and b 0 Consider (5ab) to be a single constant 5abx /(5ab) = c /(5ab) x = c /(5ab) Table 1210 Process for solving the equation 3x /(4a) = 3, provided a 0
Reasons This is the equation we are given This will allow us to solve the equation in a streamlined fashion Multiply through by the constant (4a) Simplify both sides Divide each side by 3 Simplify each side Statements 3x /(4a) = 3 Consider (4a) to be a single constant [3x /(4a)](4a) = 3 (4a) 3x = 12a (3x)/3 = 12a /3 x = 4a 198 FirstDegree Equations in One Variable
Here s a challenge! Manipulate the following equation so it contains x all by itself on the left side, and an expression containing the constants without x on the right side Indicate, if applicable, which constants cannot equal 0 3abx /(4cd ) = k 2 Solution
We must have c 0 and d 0 because, if either of them are allowed to equal 0, the lefthand side of the equation becomes undefined Let s multiply the equation through by the quantity (4cd) We get [3abx /(4cd )](4cd ) = (4cd )k 2 which simplifies to 3abx = 4cdk 2 Now we can divide the entire equation through by the quantity (3ab) When we do this, we must insist that a 0 and b 0 That produces 3abx /(3ab) = 4cdk 2/(3ab) which simplifies to x = 4cdk 2/(3ab) That does it! We don t have to worry about the fact that one of the constants is squared The square of a constant is always another constant The variable, x, is never raised to any power (other than the first power), so the equation is a firstdegree equation Combinations of Operations
In a firstdegree equation that involves a single variable, constants can be added to or subtracted from that variable, and the variable can also be multiplied or divided by nonzero constants Examples Here are some firstdegree equations that involve combinations of sums, differences, products, and ratios: 8x 4 = 0 18x + 7 = 2 a 3x = 0 a 5 + 15x = 0
Combinations of Operations
a 8x = b 6a + 3x = 12b 6a 3x /(bc) = 24d These seven equations can all be rearranged with the morphing laws we already know, so that x appears alone on the left sides of the equality symbols, and nothing but constants appear on the right sides Here are the respective solutions: x = 1/2 x = 1/2 x = a /3 x = 1/3 a /15 x = a /8 b /8 x = 2a + 4b x = 2abc + 8bcd Are you confused
Tables 1211 through 1217 break down the solution processes for the above equations Some of the steps are combined, making the derivations less tedious than those earlier in this chapter Note that in the last original equation above (and in Table 1217), it s necessary that b 0 and c 0 Also note that an attempt has been made to put the solutions in elegant form by avoiding sums or differences in the numerators of fractions, putting fractions in lowest terms, and getting the letters for the constants in alphabetical order

