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Initializing a Variable
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One way to give a variable a value is through an assignment statement, as you have already seen Another way is by giving it an initial value when it is declared To do this, follow the variable s name with an equal sign and the value being assigned The general form of initialization is shown here: type var-name = value; Here, value is the value that is given to the variable when it is created The value must be compatible with the specified type Here are some examples:
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int count = 10; // give count an initial value of 10 char ch = 'X'; // initialize ch with the letter X float f = 12F; // f is initialized with 12
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When declaring two or more variables of the same type using a comma-separated list, you can give one or more of those variables an initial value For example:
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int a, b = 8, c = 19, d; // b and c have initializations
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In this case, only b and c are initialized
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Although the preceding examples have used only constants as initializers, C# allows variables to be initialized dynamically, using any expression valid at the point at which the variable is declared For example, here is a short program that computes the hypotenuse of a right triangle given the lengths of its two opposing sides
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// Demonstrate dynamic initialization using System; class DynInit static void // Length double s1 double s2 { Main() { of sides = 40; = 50;
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// Dynamically initialize hypot double hypot = MathSqrt( (s1 * s1) + (s2 * s2) ); ConsoleWrite("Hypotenuse of triangle with sides " + s1 + " by " + s2 + " is "); ConsoleWriteLine("{0:####}", hypot); } }
Here is the output:
Hypotenuse of triangle with sides 4 by 5 is 6403
3:
D a t a Ty p e s , L i t e r a l s , a n d Va r i a b l e s
Here, three local variables s1, s2, and hypot are declared The first two, s1 and s2, are initialized by constants However, hypot is initialized dynamically to the length of the hypotenuse Notice that the initialization involves calling MathSqrt( ) As explained, you can use any expression that is valid at the point of the initialization Since a call to MathSqrt( ) (or any other library method) is valid at this point, it can be used in the initialization of hypot The key point here is that the initialization expression can use any element valid at the time of the initialization, including calls to methods, other variables, or literals
PART I
Implicitly Typed Variables
As explained, in C# all variables must be declared Normally, a declaration includes the type of the variable, such as int or bool, followed by the name of the variable However, beginning with C# 30, it became possible to let the compiler determine the type of a local variable based on the value used to initialize it This is called an implicitly typed variable An implicitly typed variable is declared using the keyword var, and it must be initialized The compiler uses the type of the initializer to determine the type of the variable Here is an example:
var e = 27183;
Because e is initialized with a floating-point literal (whose type is double by default), the type of e is double Had e been declared like this:
var e = 27183F;
then e would have the type float, instead The following program demonstrates implicitly typed variables It reworks the program shown in the preceding section so that all variables are implicitly typed
// Demonstrate implicitly typed variables
using System; class ImplicitlyTypedVar { static void Main() { // These are now implicitly typed variables They // are of type double because their initializing // expressions are of type double var s1 = 40; var s2 = 50; // Now, hypot is implicitly typed Its type is double // because the return type of Sqrt() is double var hypot = MathSqrt( (s1 * s1) + (s2 * s2) ); ConsoleWrite("Hypotenuse of triangle with sides " + s1 + " by " + s2 + " is "); ConsoleWriteLine("{0:####}", hypot); // The following statement will not compile because // s1 is a double and cannot be assigned a decimal value
Part I:
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