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public Stack(int size) { stck = new char[size]; // allocate memory for stack tos = 0; } // Construct a Stack from a Stack public Stack(Stack ob) { tos = obtos; stck = new char[obstckLength]; // Copy elements for(int i=0; i < tos; i++) stck[i] = obstck[i]; } // Construct a stack with initial values public Stack(char[] a) { stck = new char[aLength]; for(int i = 0; i < aLength; i++) { Push(a[i]); } }
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// Push characters onto the stack public void Push(char ch) { if(tos==stckLength) { ConsoleWriteLine(" -- Stack is full"); return; } stck[tos] = ch; tos++; } // Pop a character from the stack public char Pop() { if(tos==0) { ConsoleWriteLine(" -- Stack is empty"); return (char) 0; } tos--; return stck[tos]; } }
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Appendix A: Answers to Self Tests
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// Demonstrate the Stack class class SDemo { static void Main() { // construct 10-element empty stack Stack stk1 = new Stack(10); char[] name = {'T', 'o', 'm'}; // Construct stack from array Stack stk2 = new Stack(name); char ch; int i; // Put some characters into stk1 for(i=0; i < 10; i++) stk1Push((char) ('A' + i)); // Construct stack from another stack Stack stk3 = new Stack(stk1); //Show the stacks ConsoleWrite("Contents of stk1: "); for(i=0; i < 10; i++) { ch = stk1Pop(); ConsoleWrite(ch); } ConsoleWriteLine("\n"); ConsoleWrite("Contents of stk2: "); for(i=0; i < 3; i++) { ch = stk2Pop(); ConsoleWrite(ch); } ConsoleWriteLine("\n"); ConsoleWrite("Contents of stk3: "); for(i=0; i < 10; i++) { ch = stk3Pop(); ConsoleWrite(ch); } } }
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Here is the output from the program: Contents of stk1: JIHGFEDCBA Contents of stk2: moT Contents of stk3: JIHGFEDCBA 4 void Swap(Test ob1, Test ob2) { int t; t = ob1a; ob1a = ob2a; ob2a = t; } 5 No Overloaded methods can have different return types, but they do not play a role in overload resolution Overloaded methods must have different parameter lists 6 // Display a string backwards using recursion using System; class Backwards { string str; public Backwards(string s) { str = s; } public void Backward(int idx) { if(idx != strLength-1) Backward(idx+1); ConsoleWrite(str[idx]); } } class BWDemo { static void Main() { Backwards s = new Backwards("This is a test"); sBackward(0); } } 7 Shared variables are declared as static 8 The ref modifier causes an argument to be passed by reference This allows a method to modify the contents of the argument A ref parameter can receive information passed into the method The out modifier is the same as ref, except that it cannot be used to pass a value into a method
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Appendix A: Answers to Self Tests
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9 static static static static
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void Main() void Main(string[] args) int Main() int Main(string[] args)
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10 They are all legal
7: Operator Overloading, Indexers, and Properties
1 public static ret-type operator op(param-type operand) { // operations } The operand must be of the same type as the class for which the operator is being overloaded 2 To allow the full mixing of a class type with a built-in type, you must overload an operator two ways One way has the class type as the first operand and the built-in type as the second operand The second way has the built-in type as the first operand and the class type as the second operand 3 No, the cannot be overloaded No, you cannot change the precedence of an operator 4 An indexer provides array-like accessing of an object element-type this[int index] { // The get accessor get { // Return the value specified by index } // The set accessor set { // Set the value specified by index } } 5 The get and set accessors get the value specified by the index or set the value specified by an index, respectively 6 A property provides controlled access to a value type name { get { // Get accessor code } set { // Set accessor code } }
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