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Original message: This is a test Encoded message: 01+x1+x9x,=+, Decoded message: This is a test
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As you can see, the result of two XORs using the same key produces the decoded message (Remember, this simple XOR cipher is not suitable for any real-world, practical use because it is inherently insecure)
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5: More Data Types and Operators
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The unary 1 s complement (NOT) operator reverses the state of all the bits of the operand For example, if some integer called A has the bit pattern 1001 0110, then ~A produces a result with the bit pattern 0110 1001 The following program demonstrates the NOT operator by displaying a number and its complement in binary:
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// Demonstrate the bitwise NOT using System; class NotDemo { static void Main() { sbyte b = -34; for(int t=128; t > 0; t = t/2) { if((b & t) != 0) ConsoleWrite("1 "); else ConsoleWrite("0 "); } ConsoleWriteLine(); // Reverse all bits b = (sbyte) ~b; for(int t=128; t > 0; t = t/2) { if((b & t) != 0) ConsoleWrite("1 "); else ConsoleWrite("0 "); } } }
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Use the NOT operator
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The Shift Operators
In C#, it is possible to shift the bits that comprise a value to the left or to the right by a specified amount C# defines the two bit-shift operators shown here:
<< >> Left shift Right shift
The general forms for these operators are shown here: value << num-bits value >> num-bits Here, value is the value being shifted by the number of bit positions specified by num-bits
C# 30: A Beginner s Guide
A left shift causes all bits within the specified value to be shifted left one position and a zero bit to be brought in on the right A right shift causes all bits to be shifted right one position In the case of a right shift on an unsigned value, a zero is brought in on the left In the case of a right shift on a signed value, the sign bit is preserved Recall that negative numbers are represented by setting the high-order bit of an integer to 1 Thus, if the value being shifted is negative, each right-shift brings in a 1 on the left If the value is positive, each right shift brings in a 0 on the left For both left and right shifts, the bits shifted out are lost Thus, a shift is not a rotate, and there is no way to retrieve a bit that has been shifted out Here is a program that graphically illustrates the effect of a left and right shift An integer is given an initial value of 1, which means that its low-order bit is set Then, a series of eight shifts is performed on the integer After each shift, the lower eight bits of the value are shown The process is then repeated, except that a 1 is put in the eighth bit position and right shifts are performed
// Demonstrate the shift << and >> operators using System; class ShiftDemo { static void Main() { int val = 1; for(int i = 0; i < 8; i++) { for(int t=128; t > 0; t = t/2) { if((val & t) != 0) ConsoleWrite("1 "); else ConsoleWrite("0 "); } ConsoleWriteLine(); val = val << 1; // left shift Left shift val } ConsoleWriteLine(); val = 128; for(int i = 0; i < 8; i++) { for(int t=128; t > 0; t = t/2) { if((val & t) != 0) ConsoleWrite("1 "); else ConsoleWrite("0 "); } ConsoleWriteLine(); Right shift val val = val >> 1; // right shift } } }
5: More Data Types and Operators
Ask the Expert
Q: A:
Since binary is based on powers of 2, can the shift operators be used as a shortcut for multiplying or dividing an integer by 2 Yes The bitwise shift operators can be used to perform a multiplication or division by 2 A shift left doubles a value A shift right halves it Of course, this only works as long as you are not shifting bits off one end or the other
The output from the program is shown here:
0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1
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