print barcode with vb.net A Closer Look at Methods and Classes in C#

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A Closer Look at Methods and Classes
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Here is a simple example that illustrates method overloading:
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// Demonstrate method overloading using System; class Overload { public void OvlDemo() { First version ConsoleWriteLine("No parameters"); } // Overload OvlDemo for one integer parameter Second version public void OvlDemo(int a) { ConsoleWriteLine("One parameter: " + a); } // Overload OvlDemo for two integer parameters Third version public int OvlDemo(int a, int b) { ConsoleWriteLine("Two parameters: " + a + " " + b); return a + b; } // Overload OvlDemo for two double parameters public double OvlDemo(double a, double b) { ConsoleWriteLine("Two double parameters: " + a + " "+ b); return a + b; } } class OverloadDemo { static void Main() { Overload ob = new Overload(); int resI; double resD; // Call all versions of OvlDemo() obOvlDemo(); ConsoleWriteLine(); obOvlDemo(2); ConsoleWriteLine(); resI = obOvlDemo(4, 6); ConsoleWriteLine("Result of obOvlDemo(4, 6): " + resI); ConsoleWriteLine(); resD = obOvlDemo(11, 232);
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ConsoleWriteLine("Result of obOvlDemo(11, 22): " + resD); } }
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This program generates the following output:
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No parameters One parameter: 2 Two parameters: 4 6 Result of obOvlDemo(4, 6): 10 Two double parameters: 11 22 Result of obOvlDemo(11, 22): 342
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As you can see, OvlDemo( ) is overloaded four times The first version takes no parameters, the second takes one integer parameter, the third takes two integer parameters, and the fourth takes two double parameters Notice that the first two versions of OvlDemo( ) return void and the second two return a value This is perfectly valid, but as explained, overloading is not affected one way or the other by the return type of a method Thus, attempting to use these two versions of OvlDemo( ) will cause an error
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// One OvlDemo(int) is OK public void OvlDemo(int a) { ConsoleWriteLine("One parameter: " + a); } /* Error! Two OvlDemo(int)s are not OK even though return types differ */ public int OvlDemo(int a) { ConsoleWriteLine("One parameter: " + a); return a * a; }
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Return types cannot be used to differentiate overloaded methods
As the comments suggest, the difference in their return types is an insufficient difference for the purposes of overloading As you will recall from 2, C# provides certain implicit type conversions These conversions also apply to parameters of overloaded methods For example, consider the following:
// Implicit type conversions can affect overloaded method resolution using System; class Overload2 { public void MyMeth(int x) { ConsoleWriteLine("Inside MyMeth(int): " + x); }
6:
A Closer Look at Methods and Classes
public void MyMeth(double x) { ConsoleWriteLine("Inside MyMeth(double): " + x); } } class TypeConv { static void Main() { Overload2 ob = new Overload2(); int i = 10; double d = 101; byte b = 99; short s = 10; float f = 115F;
obMyMeth(i); // calls obMyMeth(int) obMyMeth(d); // calls obMyMeth(double) obMyMeth(b); // calls obMyMeth(int) -- type conversion obMyMeth(s); // calls obMyMeth(int) -- type conversion obMyMeth(f); // calls obMyMeth(double) -- type conversion } }
The output from the program is shown here:
Inside Inside Inside Inside Inside MyMeth(int): 10 MyMeth(double): 101 MyMeth(int): 99 MyMeth(int): 10 MyMeth(double): 115
In this example, only two versions of MyMeth( ) are defined: one that has an int parameter and one that has a double parameter However, it is possible to pass MyMeth( ) a byte, short, or float value In the case of byte and short, C# automatically converts them to int Thus, MyMeth(int) is invoked In the case of float, the value is converted to double and MyMeth(double) is called It is important to understand, however, that the implicit conversions apply only if there is no direct match between the types of a parameter and an argument For example, here is the preceding program with the addition of a version of MyMeth( ) that specifies a byte parameter:
// Add MyMeth(byte) using System; class Overload2 { public void MyMeth(byte x) {
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