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month, or day it is for any serial value representing any time between January 1, 1900 and December 31, 9999 The functions to use are YEAR, MONTH, and DAY Thus, if we picked a serial value like 37986: = YEAR 37986 returns 2003; = MONTH 37986 returns 12; and = DAY 37986 returns 31 This is to say that December 31, 2003 is 37,986 days away from December 31, 1899 (January 1, 1900, being day 1 in the serial value, is 1 day away) We would get the same results if we actually used the date 12/31/2003: = YEAR 12=31=2003 returns 2003; = MONTH 12=31=2003 returns 6; and = DAY 12=31=2003 returns 16 Note: I am using here the US convention for dates, which uses the order of month/day/year Excel can be set to show different dating formats so that the serial value will appear with the correct order of days, months, and years Go to Format > Cells > Number and select Date in the Category list box Look at the drop-down box for Locale (location)
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You will have to use the double quotes on the date to mark it as a text string However, if the date were placed in another cell and the function referenced that cell, you do not have to worry about double quotes Going the other way, we can write a date using the component parts of year, month, and day For this, there is the DATE function = DATE 2003,12,31 This returns the serial value 37986, which can be formatted to appear as 12/31/2003 Because Excel functions can use the results of other functions, we can write the following in cell C1 Let s put 12/31/2003 in a separate cell, say, cell B1: = DATE YEAR B1 ,MONTH B1 ,DAY B1 This returns the same date: 12/31/2003 Now, let s return to the dating problem we had at the beginning of the chapter: How do you make a date go up by one month
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We start with 12/31/2003 in B1 To make it go up by one month, we add 1 to the MONTH In C1, we write: = DATE YEAR B1 ,MONTH B1 +1,DAY B1 This will return 1/31/2004 (January 31, 2004) Success! Building on this, let s try the next column again In D1 we add another digit to the MONTH(C1): = DATE YEAR C1 ,MONTH C1 +1,DAY C1 This returns 3/2/2004 (March 2, 2004) This is not quite right What s happening The problem arises because January has 31 days and, with this formula, we are asking Excel to give the date for something like February 31, 2004 (We had no trouble with the first formula for January, because that month has the same number of days as December) Since February in this leap year only has 29 days, Excel keeps counting until the day 31 of February, and comes up with the equivalent March 2 How do we find the ending day of each month, given that months lengths vary Instead of trying to find the ending day of each month, we could look for the first day of the next month and then subtract one day Since the first day is always day 1, this is quite easy So January 31 is really February 1 minus 1 day; February 28 is March 1 minus 1 day, and so on But wait Since Excel can deal with something like February 31 to return March 2 (or March 3 in a non-leap year), can Excel consider January 31 as being February 0, and February 28 as March 0 Yes, in fact, it can So now we have a solution for our dating problem We add an extra month to the month interval we want to go up, but specify 0 for the DAY Let s have 12/31/2003 in B1 again In C1, to make the date go up by one month, we write: = DATE YEAR B1 ,MONTH B1 +2,0 to get February 0, 2004, which is 1/31/2004
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