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int i; int j; public: void get_ij() { cout << "Enter two numbers: "; cin >> i >> j; } void put_ij() { cout << i << " " << j << "\n"; } } ; // In Y, i and j of X become protected members class Y : public X { int k; public: int get_k() { return k; } void make_k() { k = i*j; } } ; /* Z has access to i and j of X, but not to k of Y, since it is private */ class Z : public Y { public: void f(); } ; // i and j are accessible here void Z::f() { i = 2; // ok j = 3; // ok } int main() { Y var; Z var2; varget_ij(); varput_ij(); varmake_k(); cout << varget_k(); cout << "\n";
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var2f(); var2put_ij(); return 0; }
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Since Y inherits X as public, the protected elements of X become protected elements of Y, which means that they can be inherited by Z and this program compiles and runs correctly However, changing X s status in Y to private, as shown in the following program, causes Z to be denied access to i and j, and the functions get_ij( ) and put_ij( ) that access them, because they have been made private in Y
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#include <iostream> using namespace std; class X { protected: int i; int j; public: void get_ij() { cout << "Enter two numbers: "; cin >> i >> j; } void put_ij() { cout << i << " " << j << "\n"; } } ; // Now, i and j are converted to private members of Y class Y : private X { int k; public: int get_k() { return k; } void make_k() { k = i*j; } } ; /* Because i and j are private in Y, they cannot be inherited by Z */ class Z : public Y { public: void f(); } ;
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// This function no longer works void Z::f() { // i = 2; i and j are no longer accessible // j = 3; } int main() { Y var; Z var2; // // varget_ij(); varput_ij(); no longer accessible no longer accessible
varmake_k(); cout << varget_k(); cout << "\n"; var2f(); var2put_ij(); return 0; }
no longer accessible
When X is inherited as private in Y s declaration, it causes i, j, get_ij( ), and put_ij( ) to be treated as private in Y, which means they cannot be inherited by Z; thus, Z s class can no longer access them
Constructors and Destructors in Derived Classes
When using derived classes, it is important to understand how and when constructors and destructors are executed in both the base and derived classes Let s begin with constructors It is possible for a base class and a derived class to each have a constructor function (In fact, in the case of a multilayered class hierarchy, it is possible for all involved classes to have constructors, but we will start with the simplest case) When a base class contains a constructor, that constructor is executed before the constructor in the derived class For example, consider this short program:
#include <iostream> using namespace std;
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class Base { public: Base() { cout << "\nBase created\n"; } }; class D_class1 : public Base { public: D_class1() { cout << "D_class1 created\n"; } }; int main() { D_class1 d1; // do nothing but execute constructors return 0; }
This program creates an object of type D_class1 It displays this output:
Base created D_class1 created
Here, d1 is an object of type D_class1, which is derived using Base Thus, when d1 is created, first Base( ) is executed, then D_class1( ) is called It makes sense for constructors to be called in the same order in which the derivation takes place Because the base class has no knowledge of the derived class, any initialization it needs to perform is separate from and possibly prerequisite to any initialization performed by the derived class, so it must be executed first On the other hand, a destructor function in a derived class is executed before the destructor in the base The reason for this is also easy to understand Since the destruction of a base class object implies the destruction of the derived class object, the derived object s destructor must be executed before the base object is destroyed This program illustrates the order in which constructors and destructors are executed:
#include <iostream> using namespace std; class Base { public: Base() { cout << "\nBase created\n"; }
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