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static int k; void f1() { k = 99; // OK }
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extern int k; void f2() { k = 10; // error }
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The program illustrates one other important point: using one namespace does not override another When you bring a namespace into view, it simply adds its names to whatever other namespaces are currently in effect Thus, by the end of the program both std and CounterNameSpace have been added to the global namespace
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Miscellaneous C++ Topics
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Because k is defined in File One, it may be used in File One In File Two, k is specified as extern, which means that its name and type are known but that k, itself, is not actually defined When these two files are linked, the attempt to use k within File Two results in an error because there is no definition for k By preceding k with static in File One, its scope is restricted to that file and it is not available to File Two While static global declarations are still allowed in C++, a better way to accomplish this is to use an unnamed namespace For example,
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namespace { int k; } void f1() { k = 99; // OK }
File Two
extern int k; void f2() { k = 10; // error }
Here, k is also restricted to File One The use of the unnamed namespace rather than static is recommended for new code
Some Namespace Options
There may be more than one namespace declaration of the same name This allows a namespace to be split over several files or even separated within the same file For example,
#include <iostream> using namespace std; namespace NS { int i; } // namespace NS { int j; } int main() { NS::i = NS::j = 10;
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// refer to NS specifically cout << NS::i * NS::j << "\n"; // use NS namespace using namespace NS; cout << i * j; return 0; }
This program produces the following output
100 100
Here, NS is split into two pieces However, the contents of each piece are still within the same namespace, ie, NS A namespace must be declared outside of all other scopes This means that you cannot declare namespaces that are localized to a function, for example There is, however, one exception: a namespace can be nested within another Consider this program:
#include <iostream> using namespace std; namespace NS1 { int i; namespace NS2 { // a nested namespace int j; } } int main() { NS1::i = 19; // NS2::j = 10; Error, NS2 is not in view NS1::NS2::j = 10; // this is right cout << NS1::i << " "<< NS1::NS2::j << "\n";
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Miscellaneous C++ Topics
// use NS1 using namespace NS1; /* Now that NS1 is in view, NS2 can be used to refer to j */ cout << i * NS2::j; return 0; }
This program produces the following output
19 10 190
Here, the namespace NS2 is nested within NS1 Thus, when the program begins, to refer to j, you must qualify it with both the NS1 and NS2 namespaces NS2 by itself is insufficient After the statement
C++ using namespace NS1;
executes, you can refer directly to NS2, since the using statement brings NS1 into view Typically, you will not need to create namespaces for most small to medium-sized programs However, if you will be creating libraries of reusable code or if you want to ensure the widest portability, then consider wrapping your code within a namespace
The std Namespace
C++ defines its entire library in its own namespace called std This is the reason that most of the C++ programs in this book include the following statement
using namespace std;
This causes the std namespace to be brought into the current namespace, which gives you direct access to the names of the functions and classes defined within the library without having to qualify each one with std:: Of course, you can explicitly qualify each name with std:: if you like For example, the following program does not bring the library into the global namespace
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