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#include <iostream> int main() { int val; std::cout << "Enter a number: "; std::cin >> val; std::cout << "This is your number: "; std::cout << std::hex << val; return 0; }
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Here, cout, cin, and the manipulator hex are explicitly qualified by their namespace That is, to write to standard output, you must specify std::cout; to read from standard input, you must use std::cin; and the hex manipulator must be referred to as std::hex You may not want to bring the standard C++ library into the global namespace if your program will be making only limited use of it However, if your program contains hundreds of references to library names, then including std in the current namespace is far easier than qualifying each name individually If you are using only a few names from the C++ library, it may make more sense to specify a using statement for each individually The advantage to this approach is that you can still use those names without an std:: qualification but you will not be bringing the entire standard library into the global namespace For example,
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// Bring only a few names into the global namespace #include <iostream> // gain access to cout, cin, and hex using std::cout; using std::cin; using std::hex; int main() { int val; cout << "Enter a number: ";
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cin >> val; cout << "This is your number: "; cout << hex << val; return 0; }
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Here, cin, cout, and hex may be used directly, but the rest of the std namespace has not been brought into view As explained, the original C++ library was defined in the global namespace If you will converting older C++ programs (including those developed using earlier versions of Borland s C++ compiler), then you will need to either include a using namespace std statement or qualify each reference to a library member with std:: This is especially important if you are replacing old h header files with the modern headers Remember, the old h headers put their contents into the global namespace The modern headers put their contents into the std namespace
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The keyword explicit is used to create nonconverting constructors For example, given the following class
class MyClass { int i; public: MyClass(int j) {i = j;} // }; C++
MyClass objects can be declared as shown here:
MyClass ob1(1); MyClass ob2 = 10;
In this case, the statement
MyClass ob2 = 10;
is automatically converted into the form
MyClass ob2(10);
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However, by declaring the MyClass constructor as explicit, this automatic conversion will not be supplied Here is MyClass shown using an explicit constructor
class MyClass { int i; public: explicit MyClass(int j) {i = j;} // };
Now, only constructors of the form
MyClass ob(110);
will be allowed
typename and export
Recently, two keywords were added to C++ that relate specifically to templates: typename and export Both play specialized roles in C++ programming Each is briefly examined The typename keyword has two uses First, it can be substituted for the keyword class in a template declaration For example, the swapargs( ) template function could be specified like this:
template <typename X> void swapargs(X &a, X &b) { X temp; temp = a; a = b; b = temp; }
Here, typename specifies the generic type X There is no difference between using class and using typename in this context The second use of typename is to inform the compiler that a name used in a template declaration is a type name rather than an object name For example,
typename X::Name someObject;
ensures that X::Name is treated as a type name The export keyword can precede a template declaration Currently, for C++ Builder, it has no effect
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Miscellaneous C++ Topics
Differences Between C and C++
For the most part, C++ is a superset of C, and virtually all C programs are also C++ programs However, a few differences do exist, the most important of which are discussed here One of the most important yet subtle differences between C and C++ is the fact that in C, a function declared like this:
int f();
says nothing about any parameters to that function That is, when there is nothing specified between the parentheses following the function s name, in C this means that nothing is being stated, one way or the other, about any parameters to that function It might have parameters and it might not have parameters However, in C++, a function declaration like this means that the function does not have parameters That is, in C++, these two declarations are equivalent:
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