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Variables that are defined within a function are local variables A local variable comes into existence when the function is entered and is destroyed upon exit Thus, a local variable cannot hold its value between function calls The only exception to this rule is when the variable is declared with the static storage class specifier This causes the compiler to treat it like a global variable for storage purposes, but limits its scope to the function (See 2 for additional information on global and local variables) All functions have file scope Thus, you cannot define a function within a function This is why C and C++ are not technically block-structured languages
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If a function is to accept arguments, it must declare the parameters that will receive the values of the arguments As shown in the following function, the parameter declarations occur after the function name:
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/* return 1 if c is part of string s; 0 otherwise */ int is_in(char *s, char c) { while(*s) if(*s==c) return 1; else s++; return 0; }
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The function is_in( ) has two parameters: s and c This function returns 1 if the character c is part of the string pointed to by s; otherwise, it returns 0 As with local variables, you can make assignments to a function s formal parameters or use them in any allowable expression Even though parameters perform the special task of receiving the value of the arguments passed to the function, they behave like any other local variable
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In a computer language, there are two ways that arguments can be passed to a subroutine The first is call by value This method copies the value of an argument into the formal parameter of the subroutine In this case, changes made to the parameter have no effect on the argument Call by reference is the second way of passing arguments to a subroutine In this method, the address of an argument is copied into the parameter Inside the subroutine, the address is used to access the actual argument used in the call This means that changes made to the parameter affect the argument
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By default, C/C++ uses call by value to pass arguments In general, this means that code within a function cannot alter the arguments used to call the function Consider the following program:
#include <stdioh> int sqr(int x); int main(void) { int t=10; printf("%d %d", sqr(t), t); return 0; } int sqr(int x) { x = x*x; return x; }
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In this example, the value of the argument to sqr( ), 10, is copied into the parameter x When the assignment x = x * x takes place, only the local variable x is modified The variable t, used to call sqr( ), still has the value 10 Therefore, the output is 100 10 Remember that it is a copy of the value of the argument that is passed into a function What occurs inside the function has no effect on the variable used in the call
Creating a Call by Reference
Even though C/C++ uses call by value for passing parameters, you can create a call by reference by passing a pointer to an argument instead of passing the argument itself Since the address of the argument is passed to the function, code within the function can change the value of the argument outside the function Pointers are passed to functions just like any other argument Of course, you need to declare the parameters as pointer types For example, the function swap( ), which exchanges the values of the two integer variables pointed to by its arguments, shows how:
void swap(int *x, int *y) { int temp;
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