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Borland C++ Builder: The Complete Reference
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The following program illustrates the foregoing discussion:
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#include <stdioh> int main(void) { int num, q; int *p; num = 100; /* num is assigned 100 */ p = # /* p receives num's address */ q = *p; /* q is assigned num's value indirectly through p */ printf("%d", q); /* prints 100 */ return 0; }
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The preceding program displays the value 100 Unfortunately, the multiplication sign and the at address sign are the same, and the bitwise AND and the address of sign are the same These operators have no relationship to each other Both & and * have a higher precedence than the binary arithmetic operators You must make sure that your pointer variables always point to the correct type of data For example, when you declare a pointer to be of type int, the compiler assumes that any address it holds points to an integer value Because C allows you to assign any address to a pointer variable, the following code fragment compiles (although C++ Builder will issue a warning message) but does not produce the desired result
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#include <stdioh> int main(void) { double x, y; int *p; x = 100123; p = &x; y = *p; printf("%f", y);
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/* this will be wrong */
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return 0; THE FOUNDATION OF C++ }
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This does not assign the value of x to y Because p is declared to be an integer pointer (and assuming 32-bit integers), only 4 bytes of information will be transferred to y, not the 8 that normally make up a double In C++, it is illegal to convert one type of pointer into another without the use of an explicit type cast For this reason, the preceding program will not even compile if you try to compile it as a C++ (rather than as a C) program However, the type of error described can still occur in C++ in a more roundabout manner
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Pointer Expressions
In general, expressions involving pointers conform to the same rules as any other C/C++ expression This section will examine a few special aspects of pointer expressions
Pointer Assignments
As with any variable, a pointer may be used on the right-hand side of assignment statements to assign its value to another pointer For example:
#include <stdioh> int main(void) { int x; int *p1, *p2; p1 = &x; p2 = p1; /* This will display the addresses held by p1 and p2 They will be the same */ printf("%p %p", p1, p2); return 0; }
Here, both p1 and p2 will contain the address of x
Borland C++ Builder: The Complete Reference
Pointer Arithmetic
Only two arithmetic operations can be used on pointers: addition and subtraction To understand what occurs in pointer arithmetic, let p1 be a pointer to an integer with a current value of 2000, and assume that integers are 4 bytes long After the expression
p1++;
the content of p1 is 2004, not 2001! Each time p1 is incremented, it points to the next integer The same is true of decrements For example,
p1--;
will cause p1 to have the value 1996, assuming that it previously was 2000 Generalizing from the preceding example, the following rules govern pointer arithmetic Each time a pointer is incremented, it points to the memory location of the next element of its base type Each time it is decremented, it points to the location of the previous element When applied to character pointers, this will appear as normal arithmetic because characters are always 1 byte long All other pointers will increase or decrease by the length of the data type they point to This approach ensures that a pointer is always pointing to an appropriate element of its base type Figure 6-2 illustrates this concept You are not limited to the increment and decrement operations, however You may also add or subtract integers to or from pointers The expression
p1 = p1 + 9;
makes p1 point to the ninth element of p1 s type beyond the one it is currently pointing to Besides addition and subtraction of a pointer and an integer, the only other operation you can perform on a pointer is to subtract it from another pointer For the most part, subtracting one pointer from another only makes sense when both pointers point to a common object, such as an array The subtraction then yields the number of elements of the base type separating the two pointer values Aside from these operations, no other arithmetic operations can be performed on pointers You cannot multiply or divide pointers; you cannot add pointers; you cannot apply the bitwise shift and mask operators to them; and you cannot add or subtract type float or double to pointers
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