Step 2: Satisfy Host and Network Requirements in Objective-C

Generation QR Code JIS X 0510 in Objective-C Step 2: Satisfy Host and Network Requirements

Step 2: Satisfy Host and Network Requirements
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In the second step, you ll use three formulas:
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2S >= number of networks you need (S represents subnet bits) 2H 2 >= number of hosts on your largest segment (H represents host bits) S + H <= total number of host bits you have for a class of address
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In the first step, you need to figure out how many bits you need to steal from the host bits to create your subnets In the second step, you need to figure out how many host bits you need to accommodate your host requirements And last, you need to make sure that when you add up the bits that you stole for subnets and the bits that
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you need for your hosts, you don t exceed the original number of host bits that you started out with, based on the Class A, B, or C network As an example, if you had a Class C network and were subnetting it and needed 5 bits for subnets and 4 bits for hosts, this would total 9 bits Unfortunately, Class C networks have only 8 host bits to begin with, so this wouldn t work In this situation, you would need either a Class B network or two Class C networks As another example, if you had the same Class C network and were subnetting it, and you needed 3 bits for subnets and 4 bits for host addresses, this would total 7 bits In this situation, the Class C network has 8 bits, and you need only 7 This gives you some flexibility you could use the extra bit either to create more subnets or have subnets with more hosts Let s go back to the original example of 19216810, where you need 14 subnets with a maximum of 14 hosts on each: 1 2S >= 14 subnets; in this example, S = 4, which would result in 16 subnets 2 2H 2 >= 14 hosts; in this example, H = 4, which would result in 14 hosts 3 S + H <= 8 (Class C network); in this example 4 + 4 is less than or equal to 8 Let s break this down step-by-step In the first step, you need to find a power of 2 that will provide a number that is either greater than or equal to the number of subnets that you need In our example, the power of 2 needs to be 4: 24 >= 16 This meets your subnet requirements, since you need only 14 subnets (there are only 14 segments) If subnet 0 were not available, then you would need 5 subnet bits instead of 4, since you would lose the first and last subnets; however, I m assuming that subnet 0 is available in this example In the second step, you need to figure out your host bits by using the formula 2H 2 >= 14 required hosts, where H is the necessary number of host bits In this example, 24 2 = 14, so you need 4 host bits to get your required 14 hosts Remember that you need to subtract 2 since the first address in the network is the network address and the last is the directed broadcast address And third, since you are dealing with a Class C network, you have only 8 original host bits You need to make sure that the total of your subnetting and host bits does not exceed this original value In your case, 4 + 4 = 8, so you re okay If the number of bits totaled more than 8, you would need two Class C networks or a Class B network If the number of bits were less than 8, you could allocate the extra bit or bits to create more subnets and/or hosts Remember that if you are ever in a situation where you have extra bits to deal with, you need to examine your network closely and figure out, based on future growth, whether you should create more subnets or allow for more hosts on a subnet
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