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Page 189
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Declaring a Structure Pointer Like other pointers, structure pointers are declared by placing * in front of a structure variable's name For example, assuming the previously defined structure addr, the following declares addr_pointer as a pointer to data of that type:
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struct addr *addr_pointer;
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Using Structure Pointers There are two primary uses for structure pointers: to pass a structure to a function using call by reference and to create linked lists and other dynamic data structures that rely on dynamic allocation This chapter covers the first use There is one major drawback to passing all but the simplest structures to functions: the overhead needed to push the structure onto the stack when the function call is executed (Recall that arguments are passed to functions on the stack) For simple structures with few members, this overhead is not too great If the structure contains many members, however, or if some of its members are arrays, run-time performance may degrade to unacceptable levels The solution to this problem is to pass a pointer to the structure When a pointer to a structure is passed to a function, only the address of the structure is pushed on the stack This makes for very fast function calls A second advantage, in some cases, is that passing a pointer makes it possible for the function to modify the contents of the structure used as the argument To find the address of a structure variable, place the & operator before the structure's name For example, given the following fragment,
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struct bal { float balance; char name[80]; } person; struct bal *p; /* declare a structure pointer */
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this places the address of the structure person into the pointer p:
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p = &person;
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To access the members of a structure using a pointer to that structure, you must use the operator > For example, this references the balance field:
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The usually called the arrow operator, consists of the minus sign followed by a greater than >, sign The arrow is used in place of the dot operator when you are accessing a structure member through a pointer to the structure To see how a structure pointer can be used, examine this simple program, which displays the hours, minutes, and seconds using a software timer:
/* Display a software timer */ #include <stdioh> #define DELAY 128000 struct my_time { int hours; int minutes; int seconds; } ; void display(struct my_time *t); void update(struct my_time *t); void delay(void); int main(void) { struct my_time systime; systimehours = 0; systimeminutes = 0; systimeseconds = 0; for(;;) { update(&systime); display(&systime); } return 0; } void update(struct my_time *t) { t->seconds++; if(t->seconds==60) { t->seconds = 0;
Page 191 t->minutes++; } if(t->minutes==60) { t->minutes = 0; t->hours++; } if(t->hours==24) t->hours = 0; delay(); } void display(struct my_time *t) { printf("%02d:", t->hours); printf(''%02d:", t->minutes); printf("%02d\n", t->seconds); } void delay(void) { long int t; /* change this as needed */ for(t=l; t<DELAY; ++t) ; }
The timing of this program is adjusted by changing the definition of DELAY As you can see, a global structure called my_time is defined, but no variable is declared Inside main( ), the structure systime is declared and initialized to 00:00:00 This means that systime is known directly only to the main( ) function The functions update( ) (which changes the time) and display( ) (which prints the time) are passed the address of systime In both functions, their arguments are declared as a pointer to a my_time structure Inside update( ) and display( ), each member of systime is accessed via a pointer Because update ( ) receives a pointer to the systime structure, it can update its value For example, to set the hours back to 0 when 24:00:00 is reached, update( ) contains this line of code:
if(t->hours==24) t->hours = 0;
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