excel barcodes 2010 C++: The Complete Reference in Visual Studio .NET

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C++: The Complete Reference
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return a[i]; } int main() { atype<int, 100> intarray; // integer array, size 100 atype<double> doublearray; // double array, default size atype<> defarray; // default to int array of size 10 int i; cout << "int array: "; for(i=0; i<100; i++) intarray[i] = i; for(i=0; i<100; i++) cout << intarray[i] << " cout << '\n';
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cout << "double array: "; for(i=0; i<10; i++) doublearray[i] = (double) i/3; for(i=0; i<10; i++) cout << doublearray[i] << " "; cout << '\n'; cout << "defarray array: "; for(i=0; i<10; i++) defarray[i] = i; for(i=0; i<10; i++) cout << defarray[i] << " cout << '\n'; return 0; }
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Pay close attention to this line:
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template <class AType=int, int size=10> class atype {
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Here, AType defaults to type int, and size defaults to 10 As the program illustrates, atype objects can be created three ways: explicitly specifying both the type and size of the array explicitly specifying the type, but letting the size default to 10 letting the type default to int and the size default to 10
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The use of default arguments especially default types adds versatility to your template classes You can provide a default for the type of data most commonly used while still allowing the user of your classes to specialize them as needed
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Explicit Class Specializations
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As with template functions, you can create an explicit specialization of a generic class To do so, use the template<> construct, which works the same as it does for explicit function specializations For example:
// Demonstrate class specialization #include <iostream> using namespace std; template <class T> class myclass { T x; public: myclass(T a) { cout << "Inside generic myclass\n"; x = a; } T getx() { return x; } }; // Explicit specialization for int template <> class myclass<int> { int x; public: myclass(int a) { cout << "Inside myclass<int> specialization\n"; x = a * a; } int getx() { return x; } }; int main() { myclass<double> d(101); cout << "double: " << dgetx() << "\n\n"; myclass<int> i(5);
C++: The Complete Reference
cout << "int: " << igetx() << "\n"; return 0; }
This program displays the following output:
Inside generic myclass double: 101 Inside myclass<int> specialization int: 25
In the program, pay close attention to this line:
template <> class myclass<int> {
It tells the compiler that an explicit integer specialization of myclass is being created This same general syntax is used for any type of class specialization Explicit class specialization expands the utility of generic classes because it lets you easily handle one or two special cases while allowing all others to be automatically processed by the compiler Of course, if you find that you are creating too many specializations, you are probably better off not using a template class in the first place
The typename and export Keywords
Recently, two keywords were added to C++ that relate specifically to templates: typename and export Both play specialized roles in C++ programming Each is briefly examined The typename keyword has two uses First, as mentioned earlier, it can be substituted for the keyword class in a template declaration For example, the swapargs( ) template function could be specified like this:
template <typename X> void swapargs(X &a, X &b) { X temp; temp = a;
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Te m p l a t e s
a = b; b = temp; }
Here, typename specifies the generic type X There is no difference between using class and using typename in this context The second use of typename is to inform the compiler that a name used in a template declaration is a type name rather than an object name For example,
typename X::Name someObject; C++
ensures that X::Name is treated as a type name The export keyword can precede a template declaration It allows other files to use a template declared in a different file by specifying only its declaration rather than duplicating its entire definition
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