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Its value is 5300. Solution to Question 3-10. A string literal consists of characters enclosed in double quotes.
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3: C# Language Fundamentals |
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Exercise Solutions
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Solution to Exercise 3-1. We ll start easy for this project. Write a short program that creates five variables, one of each of the following types: int, float, double, char, and string. Name the variables whatever you like. Initialize the variables with the following values: int: 42 float: 98.6 double: 12345.6789 char: Z string: The quick brown fox jumped over the lazy dogs. Then output the values to the console. This exercise isn t too much different from the examples in the chapter, particularly Example 3-3. The only difference is that here, you re using a variety of different data types instead of just int, and that the different types have slightly different syntax. Remember to append an f after the value for the float, to put the value for the char in single quotes, and to put the string in double quotes, and you ll be fine. If you should happen to get any of those wrong, don t worry; the compiler will provide an error message to let you know where you went wrong. One solution is shown in Example A-2.
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Example A-2. One solution to Exercise 3-1
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using using using using System; System.Collections.Generic; System.Linq; System.Text;
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namespace Exercise_3_1 { class Exercise { static void Main( ) { int myInt = 42; float myFloat = 98.6f; double myDouble = 12345.6789; char myChar = 'Z'; string myString = "The quick brown fox jumped over the lazy dogs."; Console.WriteLine("myInt: {0}, myFloat: {1}, myDouble: {2}, myChar: {3}, myString: {4}", myInt, myFloat, myDouble, myChar, myString); } } }
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Appendix: Answers to Quizzes and Exercises
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The output should look like this (although where the line breaks on your screen depends on the size of your console window):
myInt: 42, myFloat: 98.6, myDouble: 12345.6789, myChar: Z, myString: The quick brown fox jumped over the lazy dogs.
Solution to Exercise 3-2. As you gain more experience with programming, you ll frequently find yourself adapting some code that you wrote before, instead of writing a new program from scratch and there s no time like the present to start. Modify the program in Exercise 3-1 so that after you ve output the values of the variables the first time, you change them to the following: int: 25 float: 100.3 double: 98765.4321 char: M string: A quick movement of the enemy will jeopardize six gun boats Then output the values to the console a second time. This exercise is only marginally more difficult than the last. The only trick here is to remember that when you change the value of an existing variable, you don t need to declare the type again. If you do, you ll get an error. So, the reassignment of the int shouldn t look like this:
int myInt = 42;
If you do that, the compiler will think you re trying to create a new variable with the same name as one that already exists, and you ll get an error. Instead, you just write this:
myInt = 42;
And there you go. Example A-3 shows what the code should look like.
Example A-3. One solution to Exercise 3-2
using using using using System; System.Collections.Generic; System.Linq; System.Text;
namespace Exercise_3_2 { class Exercise { static void Main( ) { int myInt = 42; float myFloat = 98.6f; double myDouble = 12345.6789;
3: C# Language Fundamentals |
Example A-3. One solution to Exercise 3-2 (continued)
char myChar = 'Z'; string myString = "The quick brown fox jumped over the lazy dogs."; Console.WriteLine("myInt: {0}, myFloat: {1}, myDouble: {2}, myChar: {3}, myString: {4}", myInt, myFloat, myDouble, myChar, myString); myInt = 25; myFloat = 100.3f; myDouble = 98765.4321; myChar = 'M'; myString = "A quick movement of the enemy will jeopardize six gun boats."; Console.WriteLine("myInt: {0}, myFloat: {1}, myDouble: {2}, myChar: {3}, myString: {4}", myInt, myFloat, myDouble, myChar, myString); } } }
The output should look like this (again, the line breaks on your screen depend on the size of your console window):
myInt: 42, myFloat: The quick brown fox myInt: 25, myFloat: A quick movement of 98.6, myDouble: 12345.6789, myChar: Z, myString: jumped over the lazy dogs. 100.3, myDouble: 98765.4321, myChar: M, myString: the enemy will jeopardize six gun boats.
By the way, you can thank Brian s ninth-grade typing teacher for that second string; it s another sentence that uses every letter in the alphabet. Solution to Exercise 3-3. Write a new program to declare a constant double. Call the constant Pi, set its value to 3.14159, and output its value to the screen. Then change the value of Pi to 3.1 and output its value again. What happens when you try to compile this program This program is even simpler than the previous one. All you have to do is remember to use the keyword const when you declare the constant. Example A-4 shows the code.
Example A-4. One solution to Exercise 3-3
using using using using System; System.Collections.Generic; System.Linq; System.Text;
namespace Exercise_3_3 { class Exercise {
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