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Appendix: Answers to Quizzes and Exercises
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Example A-4. One solution to Exercise 3-3 (continued)
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static void Main( ) { const double Pi = 3.14159; Console.WriteLine("The value of pi is: {0}", Pi); Pi = 3.1; Console.WriteLine("The value of pi is: {0}", Pi); } } }
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This program won t compile, as you probably found out, because you re trying to assign a value to a constant. Instead, you receive a compiler error that reads, The left-hand side of an assignment must be a variable, property or indexer. You can fix the program by commenting out the reassignment line, but that just gives you two identical lines of output. If you really want to change the value of Pi, you ll either have to edit your code by hand, or not use a constant. So, when you use a constant in your code, you need to be certain that you ll never want to change it at runtime. Solution to Exercise 3-4. Write a new program and create a constant enumeration with constants for each month of the year. Give each month the value equal to its numeric place in the calendar, so January is 1, February is 2, and so on. Then output the value for June, with an appropriate message. For this exercise, you declare an enumeration just as you saw in Example 3-5. This time, though, you fill in the months of the year appropriately. When you write your Writeline( ) statement in Main( ), be sure to use the proper notation to refer to the constant you want (Months.June in this case), and remember to cast Months.June to an int. Example A-5 shows what the code should look like.
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Example A-5. One solution to Exercise 3-4
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using using using using System; System.Collections.Generic; System.Linq; System.Text;
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namespace Exercise_3_4 { class Exercise { // declare the enumeration enum Months : int { January = 1, February = 2,
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3: C# Language Fundamentals |
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Example A-5. One solution to Exercise 3-4 (continued)
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March = 3, April = 4, May = 5, June = 6, July = 7, August = 8, September = 9, October = 10, November = 11, December = 12 } static void Main(string[] args) { Console.WriteLine("June is month number {0}.", (int) Months.June); } } }
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And the output should look something like this, depending on what message you inserted:
June is month number 6.
4: Operators
Quiz Solutions
Solution to Question 4-1. The = operator is the assignment operator, used to assign a value to a variable. The == operator is the equality operator, which tests the equality of two values and returns a Boolean. Confusing the two is a very common mistake, and a common source of errors. Solution to Question 4-2. To assign the same value to multiple variables, simply chain the assignments, like this:
int a = b = c = d = 36;
Solution to Question 4-3. When you divide two doubles, the solution has a fractional portion, expressed as a decimal, as you would expect. When you divide two ints, the compiler discards any fractional remainder. Solution to Question 4-4. The purpose of the % operator is to return the remainder from an integer division. It s very useful in controlling loops, as you ll see later.
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Appendix: Answers to Quizzes and Exercises
Solution to Question 4-5. The output of the operations is: 32 6 4 (Be careful of the order of operations here; the division (8 / 4) takes place before the addition and the subtraction) Be sure to take note of the parentheses and the order of operator precedence, as discussed in Table 4-3. Solution to Question 4-6. Because the self-assignment operators are used here, the value of myInt changes with each step, forming a new input for the next step.
myInt myInt myInt myInt myInt myInt myInt myInt += 5; = 30 -= 15; = 15 *= 4; = 60 /= 3; = 20
Solution to Question 4-7. The prefix operator increments (or decrements) the original value, and then assigns the new value to the result. The postfix operator assigns the original value to the result, and then increments (or decrements) the original value. Solution to Question 4-8. The expressions evaluate to: 1. True 2. True 3. False 4. 5 (This expression evaluates to 5, not to true; remember that assignment returns the value assigned) Solution to Question 4-9. The expressions evaluate to: 1. True. x > y is true, and y < x is also true, so the entire expression is true. 2. False. x > y is true, so !(x > y) is false. 3. True. x < y is false, so !(x < y) is true. !(x < y) is true, and (x > y) is also true, so the entire expression together is true. Note that the ! is evaluated before the &&. 4. True. This one is tricky, because of the nested parentheses, but if you take it one step at a time, you can work it out. (x > y) is true, and !(x < y) is also true, so ((x > y) || !(x < y)) all evaluates to true. The other side of the &&, (x > y), is also true, so you end up with true && true, which evaluates to true. As you can see, you need to be very careful how you nest your parentheses.
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