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fe = Painting PDF 417 In None Using Barcode generator for Software Control to generate, create PDF 417 image in Software applications. PDF417 Decoder In None Using Barcode scanner for Software Control to read, scan read, scan image in Software applications. (b) is
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Code39 Drawer In None Using Barcode encoder for Software Control to generate, create Code 39 Extended image in Software applications. Encode Barcode In None Using Barcode encoder for Software Control to generate, create barcode image in Software applications. Since the machine is connected, VL = V = 1280 V 43 A threephase Yconnected 50Hz twopole synchronous machine has a stator with 2000 turns of wire per phase What rotor flux would be required to produce a terminal (linetoline) voltage of 6 kV SOLUTION The phase voltage of this machine should be V = VL / 3 = 3464 V The induced voltage per phase in this machine (which is equal to V at noload conditions) is given by the equation Bar Code Generation In None Using Barcode maker for Software Control to generate, create barcode image in Software applications. ANSI/AIM Code 128 Printer In None Using Barcode creator for Software Control to generate, create Code 128A image in Software applications. E A = 2 N C f
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Data Matrix ECC200 Encoder In VS .NET Using Barcode drawer for Reporting Service Control to generate, create Data Matrix 2d barcode image in Reporting Service applications. Decode EAN 13 In Java Using Barcode scanner for Java Control to read, scan read, scan image in Java applications. 3464 V = 00078 Wb 2 (2000 t )(50 Hz ) Making Barcode In ObjectiveC Using Barcode creation for iPhone Control to generate, create bar code image in iPhone applications. Data Matrix 2d Barcode Creation In None Using Barcode printer for Online Control to generate, create DataMatrix image in Online applications. Modify the MATLAB in Example 41 by swapping the currents flowing in any two phases What happens to the resulting net magnetic field SOLUTION This modification is very simple just swap the currents supplied to two of the three phases % Mfile: mag_field2m % Mfile to calculate the net magetic field produced % by a threephase stator % Set up the basic conditions bmax = 1; % Normalize bmax to 1 freq = 60; % 60 Hz w = 2*pi*freq; % angluar velocity (rad/s) % First, generate the three component magnetic fields t = 0:1/6000:1/60; Baa = sin(w*t) * (cos(0) + j*sin(0)); Bbb = sin(w*t+2*pi/3) * (cos(2*pi/3) + j*sin(2*pi/3)); Bcc = sin(w*t2*pi/3) * (cos(2*pi/3) + j*sin(2*pi/3)); % Calculate Bnet Bnet = Baa + Bbb + Bcc; % Calculate a circle representing the expected maximum % value of Bnet circle = 15 * (cos(w*t) + j*sin(w*t)); % Plot the magnitude and direction of the resulting magnetic % fields Note that Baa is black, Bbb is blue, Bcc is % magneta, and Bnet is red for ii = 1:length(t) % Plot the reference circle plot(circle,'k'); hold on; % Plot the four magnetic fields plot([0 real(Baa(ii))],[0 imag(Baa(ii))],'k','LineWidth',2); plot([0 real(Bbb(ii))],[0 imag(Bbb(ii))],'b','LineWidth',2); plot([0 real(Bcc(ii))],[0 imag(Bcc(ii))],'m','LineWidth',2); plot([0 real(Bnet(ii))],[0 imag(Bnet(ii))],'r','LineWidth',3); axis square; axis([2 2 2 2]); drawnow; hold off; end When this program executes, the net magnetic field rotates clockwise, instead of counterclockwise
45 If an ac machine has the rotor and stator magnetic fields shown in Figure P41, what is the direction of the induced torque in the machine Is the machine acting as a motor or generator SOLUTION Since ind = kB R B net , the induced torque is clockwise, opposite the direction of motion The machine is acting as a generator 5: Synchronous Machines
51 At a location in Europe, it is necessary to supply 300 kW of 60Hz power The only power sources available operate at 50 Hz It is decided to generate the power by means of a motorgenerator set consisting of a synchronous motor driving a synchronous generator How many poles should each of the two machines have in order to convert 50Hz power to 60Hz power SOLUTION The speed of a synchronous machine is related to its frequency by the equation nm =
120 f e P
To make a 50 Hz and a 60 Hz machine have the same mechanical speed so that they can be coupled together, we see that nsync =
120(50 Hz ) 120(60 Hz ) = P1 P2
P2 6 12 = = P1 5 10
Therefore, a 10pole synchronous motor must be coupled to a 12pole synchronous generator to accomplish this frequency conversion 52 A 480V 200kVA 08powerfactorlagging 60Hz twopole Yconnected synchronous generator has a synchronous reactance of 025 and an armature resistance of 003 At 60 Hz, its friction and windage losses are 6 kW, and its core losses are 4 kW The field circuit has a dc voltage of 200 V, and the maximum I F is 10 A The resistance of the field circuit is adjustable over the range from 20 to 200 The OCC of this generator is shown in Figure P51 (a) How much field current is required to make VT equal to 480 V when the generator is running at no load (b) What is the internal generated voltage of this machine at rated conditions (c) How much field current is required to make VT equal to 480 V when the generator is running at rated conditions (d) How much power and torque must the generator s prime mover be capable of supplying SOLUTION (a) If the noload terminal voltage is 480 V, the required field current can be read directly from the opencircuit characteristic It is 455 A (b) This generator is Yconnected, so I L = I A At rated conditions, the line and phase current in this generator is

