zxing barcode reader java download Y11 = YLine 1 + YLine 2 = 38102 j177929 in Software

Making PDF-417 2d barcode in Software Y11 = YLine 1 + YLine 2 = 38102 j177929

Y11 = YLine 1 + YLine 2 = 38102 j177929
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and the off-axis admittance Y12 between Bus 1 and Bus 2 is 13071 + j77804 The complete bus admittance matrix is
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38102 j177929 13071 + j 77804 = 0 25031 + j100125 0 55723 j 271804 10811 + j 64865 0 31842 + j129135 10811 + j 64865 28293 j152277 0 17483 + j87413 0 53134 j 218451 28102 + j118326 31842 + j129135 17483 + j87413 28102 + j118326 77426 j 334873 0 13071 + j 77804 25031 + j100125 0
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Ybus
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Once we have created Ybus , we can write a program that iteratively calculates the bus voltages until it converges to an answer As stated above, the program can be in any language that you wish to use However, it is easiest to write such a program in MATLAB or Fortran, because those languages include a native complex number type Languages such as C are much harder to use, because the programmer must manually perform all complex calculations A MATLAB version of the program is shown below:
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% % % % M-file: prob11_8m M-file to solve the power-flow problem of Problem 11-8 This set of equations includes a slack bus, a generator bus, and three load busses
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% Set problem size and initial conditions
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n_bus = 5; swing_bus = 1; acc_fac = 13; % Specify which busses are generator busses with flags % Note that 1 is "true" and 0 is "false" in MATLAB In % this example, Bus 5 is a generator bus, and the others % are not gen_bus = [0 0 0 0 1]; % Create Y-bus
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Ybus = [ 38102-j*177929 -13071+j*77804 -13071+j*77804 0 -25031+j*100125 0 -10811+j*64865 0 0 -25031+j*100125 0 0; -17483+j*87413; 77426-j*334873]; 55723-j*271804 -10811+j*64865 0 -31842+j*129135;
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28293-j*152277 0
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53134-j*218451 -28102+j*118326;
-31842+j*129135 -17483+j*87413 -28102+j*118326
% Initialize the real and reactive power supplied to the % power system at each bus Note that the power at the % swing bus doesn't matter, and the reactive power at the % generator bus will be recomputed dynamically P(2) = -06; P(3) = -07; P(4) = -08; P(5) = 15; Q(2) = -035; Q(3) = -04; Q(4) = -05; Q(5) = -03; % Initialize the bus voltages to 10 at 0 degrees for ii = 1:n_bus Vbus(ii) = 1; end % Set convergence criterion eps = 000001; % Initialize the iteration counter n_iter = 0; % Set a maximum number of iterations here so that % the program will not run in an infinite loop if % it fails to converge to a solution for iter = 1:100 % Increment the iteration count n_iter = n_iter + 1; % Save old bus voltages for comparison purposes Vbus_old = Vbus; % Calculate the updated bus voltage for ii = 1:n_bus
% Skip the swing bus! if ii ~= swing_bus % If this is a generator bus, update the reactive % power estimate if gen_bus(ii) temp = 0; for jj = 1:n_bus temp = temp + Ybus(ii,jj) * Vbus(jj); end temp = conj(Vbus(ii)) * temp; Q(ii) = -imag(temp); end % Calculate updated voltage at bus 'ii' First, sum % up the current contributions at bus 'ii' from all % other busses temp = 0; for jj = 1:n_bus if ii ~= jj temp = temp - Ybus(ii,jj) * Vbus(jj); end end % Add in the current injected at this node temp = (P(ii) - j*Q(ii)) / conj(Vbus(ii)) + temp; % Get updated estimate of Vbus at 'ii' Vnew = 1/Ybus(ii,ii) * temp; % Apply an acceleration factor to the new voltage estimate Vbus(ii) = Vbus_old(ii) + acc_fac * (Vnew - Vbus_old(ii)); % If this is a generator bus, update the magnitude of the % voltage to keep it constant if gen_bus(ii) Vbus(ii) = Vbus(ii) * abs(Vbus_old(ii)) / abs(Vbus(ii)); end end end % Compare the old and new estimate of the voltages % Note that we will compare the real and the imag parts % separately, and both must be within tolerances test = 0; for ii = 1:n_bus % Compare real parts if abs( real(Vbus(ii)) - real(Vbus_old(ii)) ) > eps test = 1; end % Compare imaginary parts if abs( imag(Vbus(ii)) - imag(Vbus_old(ii)) ) > eps test = 1; end
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