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// Display the contents of a vector<int> template<class T> void show(const char *msg, vector<T> vect) { cout << msg; for(unsigned i=0; i < vectsize(); ++i) cout << vect[i] << " "; cout << "\n"; } // Return the whole-number midpoint between two values int midpoint(int a, int b) { return((a-b) / 2) + b; } // Return the reciprocal of a double double reciprocal(double val) { if(val == 00) return 00; return 10 / val; // return reciprocal }
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Demonstrate single-sequence form of transform() Initial contents of v: 1 2 3 4 5 6 7 8 9 Compute reciprocals for Transformed contents of 1 05 0333333 025 02 Transform v again This Here is v2: 1 2 3 4 5 6 7 8 9 0 v and store the results back in v v: 0166667 0142857 0125 0111111 time, store the results in v2
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Demonstrate double-sequence form of transform() Contents of v3: 0 1 2 3 4 5 6 7 8 9 Contents of v4: -10 11 -12 13 -14 15 -16 17 -18 19 Compute midpoints between v3 and v4 and store the results in v5 Contents of v5: -5 6 -5 8 -5 10 -5 12 -5 14
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A key point illustrated by the program is that the function or function object used by transform( ) must specify a parameter or parameters whose types are compatible with the types of the elements in the sequences Also, it must return a compatible type
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The ranges specified in the two-sequence version of transform( ) do not need to be in separate containers This is a common misconception Instead, you can specify both ranges from the same container For example, assuming the preceding program, the following
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computes the midpoints between the first and last five elements of v3 and stores them in the first five elements of v5:
transform(v3begin(), v3begin()+5, v3begin()+5, v5begin(), midpoint);
As mentioned, it is possible to store the result back into one of the original sequences, thus allowing a sequence to be modified in-place When using the two-sequence form of transform( ), the target sequence can be either of the input sequences For example, this statement computes the midpoints for the sequences held in v3 and v4 and stores the result in v4:
transform(v3begin(), v3end(), v4begin(), v4begin(), midpoint);
This works because the values of each pair of elements are first obtained from each sequence and then passed to midpoint( ) The result is then stored in v4 Thus, the original values in v4 are obtained before they are overwritten The preceding example passed function pointers to transform( ), but you can also use function objects Function objects are described in detail in Use a Built-In Function Object and Create a Custom Function Object For an example that uses a function object with transform( ), see Create a Custom Function Object If you want to perform a non-modifying operation on a sequence, consider using for_each( ) See Cycle Through a Container with for_each( ) In some cases, you may want to generate a sequence of elements that are not transformations of another sequence To do this, you can use the generate( ) or generate_n( ) algorithms They are shown here: template <class ForIter, class Generator> void generate(ForIter start, ForIter end, Generator fngen) template <class OutIter, class Size, class Generator> void generate_n(OutIter start, Size num, Generator fngen) The algorithms generate( ) and generate_n( ) assign values returned by a generator function to elements within a specified range For generate( ), the range being assigned is specified by start and end For generate_n( ), the range begins at start and runs for num elements The generator function is passed in fngen It has no parameters and it must return objects that are compatible with the type of the desired sequence Here is a very simple example that demonstrates generate( ) It uses a function called pow_of_two( ) to generate a sequence that contains powers of 2
// Generate a sequence #include <iostream> #include <vector> #include <algorithm> using namespace std; double pow_of_two();
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