java ean 13 Discrete Mathematics Demystified in Java

Printer GTIN - 12 in Java Discrete Mathematics Demystified

Discrete Mathematics Demystified
UPCA Encoder In Java
Using Barcode generation for Java Control to generate, create UPC Code image in Java applications.
Reading UPC Symbol In Java
Using Barcode decoder for Java Control to read, scan read, scan image in Java applications.
Figure 71 Typical (empty) intersection of three lines in the plane
Print Barcode In Java
Using Barcode generation for Java Control to generate, create bar code image in Java applications.
Recognizing Barcode In Java
Using Barcode reader for Java Control to read, scan read, scan image in Java applications.
Matters are more complicated for systems of three equations in three unknowns, or more generally k equations in k unknowns It becomes dif cult to keep track of the information, and the attendant calculations can be daunting In this section we introduce the method of Gaussian elimination, which gives a straightforward and virtually mechanical method for solving systems of linear equations In fact it is straightforward to implement the method of Gaussian elimination on a computer; for a system of k equations in k unknowns it takes about k 3 calculations to nd the solution So this is a robust and ef cient technique We concentrate our efforts on systems of k equations in k unknowns because such a system will generically have a unique solution (that is, a single value for each of the variables that solves the system) When there are fewer unknowns than equations then the system will typically have no solutions1 When there are more unknowns than equations then the system will typically have an entire space of solutions For example, the solution of the system x+z =4 z=3
Generating UPC-A Supplement 5 In Visual C#.NET
Using Barcode generator for VS .NET Control to generate, create Universal Product Code version A image in .NET applications.
UPC Code Creator In .NET Framework
Using Barcode printer for ASP.NET Control to generate, create UCC - 12 image in ASP.NET applications.
1 Think of intersecting lines in the plane Two lines in the plane will usually have a point of intersection as long as they are not parallel Three lines in the plane will usually not have a mutual point of intersection see Fig 71
Print UCC - 12 In .NET
Using Barcode maker for VS .NET Control to generate, create UPC-A Supplement 5 image in VS .NET applications.
Print UPC-A Supplement 2 In Visual Basic .NET
Using Barcode drawer for Visual Studio .NET Control to generate, create GTIN - 12 image in .NET framework applications.
Matrices
Making Matrix 2D Barcode In Java
Using Barcode maker for Java Control to generate, create Matrix 2D Barcode image in Java applications.
Encode Code 39 In Java
Using Barcode creation for Java Control to generate, create ANSI/AIM Code 39 image in Java applications.
are all points of the form (1, y, 3) In other words, the set of solutions forms an entire line It requires ideas from linear algebra to handle these matters properly, and we cannot treat them here So we will focus our attention on k equations in k unknowns In the method of Gaussian elimination we will typically have a system of equations
Making Code 39 Full ASCII In Java
Using Barcode creation for Java Control to generate, create Code 39 image in Java applications.
ECC200 Printer In Java
Using Barcode creation for Java Control to generate, create ECC200 image in Java applications.
1 1 1 a1 x 1 + a2 x 2 + a3 x 3 + + ak 1 x k = 2 2 2 2 a1 x 1 + a2 x 2 + a3 x 3 + + ak 2 x k = 2
Making RM4SCC In Java
Using Barcode drawer for Java Control to generate, create RM4SCC image in Java applications.
Printing Linear 1D Barcode In .NET
Using Barcode maker for ASP.NET Control to generate, create 1D image in ASP.NET applications.
k k k a1 x 1 + a2 x 2 + a3 x 3 + + ak k x k = k
Matrix Barcode Generation In C#
Using Barcode printer for Visual Studio .NET Control to generate, create 2D Barcode image in .NET applications.
Recognizing Universal Product Code Version A In C#
Using Barcode decoder for .NET Control to read, scan read, scan image in Visual Studio .NET applications.
We will study this system by creating the associated augmented matrix 1 a1 a 2 1 k a1
Decoding GS1-128 In Visual Basic .NET
Using Barcode recognizer for Visual Studio .NET Control to read, scan read, scan image in VS .NET applications.
1D Barcode Drawer In Visual Basic .NET
Using Barcode maker for Visual Studio .NET Control to generate, create 1D Barcode image in Visual Studio .NET applications.
1 a2 2 a2 k a2 1 a3 2 a3 k a3
Create Code 128 Code Set C In Visual Studio .NET
Using Barcode printer for VS .NET Control to generate, create USS Code 128 image in .NET applications.
DataMatrix Creation In Visual Studio .NET
Using Barcode printer for Reporting Service Control to generate, create Data Matrix ECC200 image in Reporting Service applications.
1 ak 1 2 ak 2 k k ak
Now there are certain allowable operations on the augmented matrix that we use to reduce it to a normalized form The main diagonal of this matrix is the line of k 1 2 terms given by a1 , a2 , , ak We want all the terms below this main diagonal to be equal to 0 And we want the terms on the main diagonal to all be 1s The three allowable operations are: 1 Switch the position of two rows 2 Multiply any row by a nonzero constant 3 Add a multiple of one row to another It turns out that these three simple moves are always adequate to do the job The ideas are best illustrated with some examples EXAMPLE 75 Let us solve the system x 2y + 3z = 4 x + y + z = 2 x + 2y + z = 1
Discrete Mathematics Demystified
using Gaussian elimination We begin by writing the augmented matrix: 1 1 1 2 3 1 1 2 1 4 2 1
Keeping in mind that our aim is to produce all zeros below the main diagonal, we subtract the rst row from the second This yields 1 2 0 3 1 2 3 2 1 4 6 1
This produces a zero below the main diagonal Next we add the rst row to the last The result is 1 0 0 2 3 3 2 0 4 4 6 5
Finally let us multiply the second row by 1/3 and the third row by 1/4 The end result is 1 0 0 2 3 1 2/3 0 1 4 2 5/4
This is the normalized form that we seek Writing our information again as a linear system, we have x 2y + 3z = 4 0x + 1y 2/3z = 2 0x + 0y + z = 5/4 We may immediately read off from the last equation that z = 5/4 Substituting this information into the second equation gives y = 7/6 Lastly, putting both these values into the rst equation yields x = 25/12 Thus the solution of our system is x = 25/12, y = 7/6, z = 5/4 or ( 25/12, 7/6, 5/4)
Copyright © OnBarcode.com . All rights reserved.