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IT EA = ER = EL
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2 2 IT = I R + I L
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IT E A = E R = EC
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2 2 I T = I R + IC
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IT PF = Cos q TP = AP PF Phase = q
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Cos q =
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IT PF = Cos q TP = AP PF Phase = q
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Parallel RCL Circuits Z= EA Cos q = IR
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IT E A = E R = E L = EC
2 I T = I R + ( I L I C )2
Phase = q
IT TP = AP PF (Watts) AP = V A (Volt-Amperes) PF = Cos q
Antiresonance Parallel LC Circuits X L = XC Z = maximum ( ) I line = minimum (0) or Tank Circuits I circulating = I C or I L IC = EA XC IL = EA XL
CHAPTER FOURTEEN
electromotive force E divided by the resistance R Or, in mathematical terms I= E R (14-1)
Figure 14-1 shows how you can develop the formula for Ohm s law rather quickly and accurately Let your nger cover the letter representing the value you are looking for, and the remaining two letters will show you the relationship between them by being situated either one on top of the other (division) or one next to the other (multiplication)
EXAMPLE 14-1
A resistor has a voltage of 120 volts applied to its 40 ohms of resistance What is the current that will ow through the resistor Step 1 Decide which formula to use Since the unknown is the current I, the formula to use is I= E R (14-2)
FIGURE 14-1 Graphic representation of Ohm s law
ELECTRICAL AND ELECTRONIC FORMULAS
Step 2 Substitute the known values voltage E and resistance R in the formula I= 120 40 (14-3)
Step 3 Perform the mathematical operation in this case, division I = 3 amperes
EXAMPLE 14-2
How much voltage do you need to cause 2 amperes to ow through a resistance of 20 ohms Step 1 Decide which formula to use Since the unknown is the voltage E, the formula to use is E=I R Step 2 Substitute the known values the current I and resistance R in the formula E = 2 20 Step 3 Perform the mathematical operation in this case, multiplication E = 40 volts
EXAMPLE 14-3
What is the resistance of a circuit that has a voltage source of 24 volts pushing 6 amperes through a resistor Step 1 Determine the unknown and use the appropriate formula R= E I (14-4)
CHAPTER FOURTEEN
Step 2 Substitute the known values in the formula R= 24 6 (14-5)
Step 3 Perform the mathematical operation R = 4 ohms
USING POWER FORMULAS
A certain amount of power is expended whenever an electric current is passed through a load, such as a resistor This energy is dissipated in the form of heat, which must be dissipated into the surrounding medium The amount of heat that can be dissipated from the surface of the resistor determines its wattage rating, or power rating The unit of measure for electric power is the watt W The watt was named for James Watt (1736 1819), a Scottish engineer and the inventor of the modern condensing steam engine, one of the rst sources of mechanical power The watt is mathematically equal to the product of the voltage E and current I, P(power in watts) = E I Many relationships between P, E, R, and I can be obtained by using simple algebra P = E I I= P E P= E2 R (14-7) (14-6)
P = I 2R
EXAMPLE 14-4
What is the power consumed by an electric iron that has 120 volts at 10 amperes
ELECTRICAL AND ELECTRONIC FORMULAS
Step 1 Determine which formula to use Since you know the voltage E and the current I, the formula to use is P=E I Step 2 Substitute the known values in the formula P = 120 10 Step 3 Perform the mathematical computation P = 1200 watts
EXAMPLE 14-5
How much current does a 120-volt, 60-watt light bulb pull Step 1 Determine which formula to use Since you know the voltage E and the wattage, or power P, the formula to use is I= P E (14-8)
Step 2 Substitute the known values in the formula I= 60 W 120 V (14-9)
Step 3 Perform the mathematical computation I = 05 ampere
EXAMPLE 14-6
What is the current required to light a 120-volt, 15-watt light bulb to full brilliance Step 1 Use the appropriate formula in this case I= P E (14-10A)
CHAPTER FOURTEEN
TABLE 14-2 Current Drawn by Different Wattage Bulbs on a 120-Volt Circuit Voltage 120
Wattage 15 25 40 60 75 100 150 200 300
Current (amperes) 01250 02083 03330 05000 06250 08333 12500 16660 25000
Step 2 Substitute the known factors in the equation I= 15 120 (14-10B)
Step 3 Perform the mathematical computation I = 0125 amperes Power formulas can be developed, and the current that each wattage of light bulb will draw on a 120-volt circuit can be determined (See Table 14-2) This type of table is handy when you need to compute how much current a circuit of so many light bulbs will draw, and it also helps in selecting the right size of wire for a job
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