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Systemoutprintln("Student Name: " + name); } } class Student extends Person { private int studentID; Student (){ studentID = 12345; } protected void displayStudentID(){ Systemoutprintln("Student ID: " + studentID); } } class GraduateStudent extends Student { protected void display(){ displayName(); displayStudentID(); } }
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Previously you learned that a method member enables an instance of a class to perform a specific kind of behavior, such as displaying instance variables on the screen A subclass inherits behavior from a superclass when a subclass can access method members of the superclass You saw this in the previous example, where the GraduateStudent class called method members of its superclass to display instance variables Sometimes the behavior of a method member of a superclass doesn t meet the needs of a subclass For example, the manner in which a superclass s method member displays an instance variable isn t exactly the way the subclass wants the instance variable displayed In this case, a programmer defines another version of the superclass s method member within the subclass and includes statements that enhance the original behavior of the superclass s method member Programmers referred to this as overriding a method member Don t confuse overriding a method member with overloading a method, which you learned about in 6 Overloading a method requires you to define a method that has the same method name but a different argument list than a method
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CHAPTER 8 Inheritance
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that is already defined That is, each method has a different signature Overriding a method member requires you to use the same method name and the same argument list as a method member defined in a subclass s superclass You might think that having two method members with the same signature will confuse Java It won t, and here s why: Java uses method members of the class whose instances call the method Therefore, if you use an instance of the subclass in your program to call the method member, Java uses the subclass s version of the method member Let s take a look at an example to see how this works The following program is a variation of the program used in the previous example Here s what is happening in this program: three classes are defined They are the Person class, the Student class, and the GraduateStudent class The Person class and the Student class both declare an instance variable, initialize the instance variable, and define a method member called display() that displays its instance variable Notice that these instance variables are designed with the protected access specifier This means they can be accessed directly by the subclass Neither version of the display() method member is suitable for the GraduateStudent class Therefore, the GraduateStudent class overrides the display() method member Statements within the new version of the display() method directly access instance variables of the Person class and the Student class An instance of the GraduateStudent class is declared in the main() method, and the instance is used to call the display() method Java uses the display() method member defined in the GraduateStudent class
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class Demo { public static void main (String args[]) { GraduateStudent gs = new GraduateStudent (); gsdisplay(); } } class Person { protected String name; Person(){ name = "Bob Smith"; } void display(){ Systemoutprintln("Person Class: " + name); } } class Student extends Person { protected int studentID;
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Student (){ studentID = 12345; } void display(){ Systemoutprintln("Student Class: " + studentID); } } class GraduateStudent extends Student { void display(){ Systemoutprintln("Graduate Student Class:"); Systemoutprintln("Name:" + name); Systemoutprintln("Student ID: " + studentID); } }
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Dynamic Method Dispatch
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Dynamic method dispatch might seem to be a term you need four years at MIT to understand However, the concept of dynamic method dispatch is rather simply to understand Let s begin by translating this term into everyday English The word dynamic refers to doing something when the program runs as opposed to when the program is compiled You ve seen this word used previously in this book when you learned how to dynamically declare an object (that is, declaring memory for an object at run time rather than compile time) Method dispatch simply means the program is calling a method member of a class Therefore, dynamic method dispatch means deciding which method member to call when your program runs rather than making that decision when your program is compiled The method member that we re talking about is a method member of a subclass that overrides a method member of a superclass You learned how to override method members in the previous section of this chapter You call a method member by using a reference to its instance, the dot operator, and the name of the method member, which you learned how to do in this chapter For example, here is how to call the display() method member of the Person class:
Person p = new Person (); pdisplay();
Suppose that the Person class is a superclass, and its subclass (called the Student class) needs to modify the behavior of the display() method member The Student class does this by overriding the display() method member You saw how to do this in the previous section of this chapter You determine which version of the display() method member to call by referencing the appropriate instance
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