# barcode in rdlc FIGURE 83 Method of calculating the amount of water in a rectangular tank or sump in .NET framework Create Quick Response Code in .NET framework FIGURE 83 Method of calculating the amount of water in a rectangular tank or sump

FIGURE 83 Method of calculating the amount of water in a rectangular tank or sump
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FIGURE 84 Calculating the amount of water in a round tank (Virginia Chemicals)
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The two formulas above will give you the water volume in either the tank or sump Each is figured separately since they are both part of the system s circulating water supply There is also water in the connecting lines These lines must be measured for total footage Once you find the pipe footage connecting the system, you can figure its volume of water Simply take 10 percent of the water volume in the sump for each 50 feet of pipe run This is added to the water in the sump and the water in the tank to find the total system water volume For example, a system has 75 gallons of water in the sump and 162 gallons of water in the tank The system has 160 feet of pipe: 75 gallons 160 feet 75 gallons 162 gallons 50 feet 32 32 10 75 gallons for every 50 feet in the pipes 24 gallons (in pipes) 261 gallons in the total system 24 gallons in the total pipe system 237 gallons
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75 gallons in sump
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237 gallons (in tank and sump)
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This is the amount of water that must be treated to keep the system operating properly Now that you have determined the volume of water in the system, you can calculate the amount of chemicals needed To clean the system: 1 2 3 Drain the sump Flush out, or remove manually, all loose sludge and dirt This is important because they waste the chemicals Close the bleed line and refill the sump with fresh water to the lowest level at which the circulating pump will operate (see Figure 85) Calculate the total gallons of water in the system Next, while the water is circulating, add starting amounts of either chemical slowly, as follows (These amounts are for hot water systems) For solid scale remover, use 5 pounds per 10 gallons of water For regular liquid scale remover, use 1 gallon per 15 gallons of water For concentrated liquid scale remover, use 1 gallon per 20 gallons of water (refer to Figure 85) The scale removers can be introduced at the water-tower distribution plate (A), the sump (B), or the water tank (C) Convenience is the keyword here The preferred addition point is directly into the pump suction area When using liquid scale remover, add 1 ampoule of antifoam reagent per gallon of chemical This will usually prevent excessive foaming if added before the scale remover Extra antifoam is available in 1-pint bottles When using the solid scale remover, stir the crystals in a plastic pail or drum until completely dissolved Then pour slowly as a liquid Loose crystals, if
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FIGURE 85 Forced- and natural-draft towers (A) Water tower distribution plate, (B) sump, (C) water tank (Virginia Chemicals)
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al1owed to fall to the bottom of the sump, will not dissolve without much stirring If not dissolved, they might damage the bottom of the sump 5 Figure 86 shows how to prepare the crystals in the drum Use a 55-gallon drum Install a drain or spigot about 6 to 8 inches from the bottom Set the drum in an upright position Fill the drum with fresh water within 6 inches from the top, preferably warm water at about 80 degrees F (27 degrees C) Since the fine particles of the water-treatment crystals are quite irritating to the nose and eyes, immerse each plastic bag in the water Cut the bag below the surface of the water (See Figure 86) Stir the crystals until dissolved About 6 to 8 pounds of crystals will dissolve in each gallon of water Drain or pump this strong solution into the system Repeat this procedure until the required weight of the chemical has been added in concentrated solution Then add fresh water to fill the system The treatment should be repeated once each year for best results