PART VIII: PCAT PRACTICE TEST in .NET Make Data Matrix ECC200 in .NET PART VIII: PCAT PRACTICE TEST

PART VIII: PCAT PRACTICE TEST
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The number of possible outcomes yielding a sum of 12 is 1 or {(6, 6)} The probability of yielding a sum of 12 between the two dice is P(B) = P(12) = 1 36
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Upon the roll of two dice, you cannot obtain a sum of 7 and a sum of 12 at the same time; thus the two outcomes are mutually exclusive The probability that the sum of the 6 1 7 + = two dice is either 7 or 12 is: P(A or B) = P(A) + P(B) = P(7) + P(12) = 36 36 36 22 Answer: B Because the two drawings are made from a complete deck of cards, the two events are independent of one another You rst need to determine the probability of drawing a card of two suits from a deck of cards Out of a total of 52 cards, there are 13 cards of any suit and 26 cards of a black suit The probability of drawing a card of a 26 black suit, P(A), is Because the rst card is replaced before the second drawing, 52 26 the probability of drawing a card of the same suit, P(B), is also Thus, the probabil52 ity of drawing two cards of the same suit is P(A and B) = P(A) P(B) = 26 26 676 = 52 52 2704
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23 Answer: C The mean of a data set is the arithmetic average of the values of the data set or 24mL + 32mL + 37mL + 37mL + 45mL + 68mL + 73mL + 81mL + 122mL 9 519mL = = 58mL 9
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PART VIII: PCAT PRACTICE TEST
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24 Answer: B The median is the middle or center value of the data set arranged in ascending numerical order, or 45 m L 25 Answer: A The mode is the measurement that is the most frequent or common value in the data set In this example, the mode is 37 m L , because it occurs twice, more than any of the other measurements that occur only once 26 Answer: D The range or the difference between the largest and smallest values in this data set is 1 2 2 m L 2 4 m L = 9 8 mL 27 Answer: D The rst thing to do in solving the equation x 2 12 x = 36 for x is to rewrite the equation by adding 36 to both sides and then to express the equation in terms of factors: x 2 12 x + 36 = 0 (x 6) (x 6) = 0 Solving the equation for x yields x = 6 28 Answer: A In order to solve the equation x 3 6 4 x = 0 for x, you can apply factor analysis and solve for x in each term: x3 64 x 0 = x x x x2 64 = 0 x = 8 29 Answer: C This equation can be solved by rst taking the square root of both sides of the equation (4 x 1)2 = 121 or
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(4x 1)2 =
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4 x 1 = 11 Solving for x yields x = 3 30 Answer: A y y1 The slope is de ned as: m = 2 If the rst point (5 , 2) = (x1,y1) and the second x2 x1 point ( 8 , 3 ) = (x2, y2), then substituting these coordinate values into the de nition for the slope yields m= 3 2 1 = 8 5 3
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31 Answer: B The slope can be identi ed by adapting the equation to the formal equation of a line or y = m x + b or 2y + 3x 12 = 0 2y = 3x + 12 2y 3x 12 = + 2 2 2 3 y = x+6 2 3 where the slope m = 2 32 Answer: C You can use the information provided by the speci c point and the value of the slope to derive the equation for the line: m= y2 y1 x2 x1
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