c Run the script to create the Address table in Visual Studio .NET

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c Run the script to create the Address table
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USE 3; GO CREATE TABLE dboAddress ( AddressID int IDENTITY(1,1) NOT NULL, AddressLine1 varchar(35) NULL, AddressLine2 varchar(35) NULL, City varchar(35) NULL, State char(2) NULL, Zip varchar(10) NULL, CONSTRAINT [PK_Address_AddressID] PRIMARY KEY CLUSTERED ( AddressID ) );
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d Run the script to modify the Employee table by adding an AddressID column as an FK to the PK in the Address table
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Alter TABLE dboEmployee ADD AddressID int NULL CONSTRAINT FK_Employee_Address FOREIGN KEY(AddressID) REFERENCES dboAddress(AddressID);
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3 Create a State table by using the following script:
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CREATE TABLE dboState ( State char(2) NOT NULL, CONSTRAINT [PK_State_State] PRIMARY KEY CLUSTERED ( State ) );
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4 Populate the State table by executing the following INSERT statements:
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INSERT INSERT INSERT INSERT INSERT INSERT INTO INTO INTO INTO INTO INTO dboState dboState dboState dboState dboState dboState VALUES('VA') VALUES('NY') VALUES('MA') VALUES('NV') VALUES('HI') VALUES('CA')
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Notice this adds six entries for Virginia (VA), New York (NY), Massachusetts (MA), Nevada (NV), Hawaii (HI), and California (CA) 5 Create an FK in the Address table pointing to the State table by running the following script:
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Alter TABLE dboAddress ADD CONSTRAINT FK_Address_State FOREIGN KEY(State) REFERENCES dboState(State);
6 Add an address in the Address table with a valid state using the following INSERT statement:
INSERT INTO dboAddress(AddressLine1, City, State, Zip) VALUES ('565 Untraveled Path','Mossey','VA','23462')
With this INSERT, we can see it s possible to add a record to the Address table: 7 Add an address with an invalid state with the following INSERT statement:
INSERT INTO dboAddress(AddressLine1, City, State, Zip) VALUES ('30 Degree Dr','Frostproof','FF','73462')
You should see an error similar to the following:
Msg 547, Level 16, State 0, Line 1 The INSERT statement conflicted with the FOREIGN KEY constraint "FK_ Address_State"
3: Database Design
The conflict occurred in database "3", table "dboState", column 'State' The statement has been terminated
8 By entering the following SELECT statement, you can verify the first row was added, but the second row was not:
SELECT * FROM Address
Table Relationships
As we ve seen with the PRIMARY KEY and FOREIGN KEY sections previously, we can create relationships between tables Usually, we match a PK in one table with an FK in another table in a one-to-many relationship However, three different kinds of relationships actually exist One-to-many relationships One-to-one relationships Many-to-many relationships
One-to-Many Relationships
In a one-to-many relationship, any row in the first table can have matches to many rows in the second table For example, consider a company that sells products from several different manufacturers Any single manufacturer (in the manufacturer table identified with the PK of ManufacturerID) could have many different products However, any single product (in the product table identified with the PK of ProductID) can only have one manufacturer We can see this in Figure 3-5 Notice the icons in the connecting line in Figure 3-5 On the PK side, we can see a key (representing one) and on the FK side is an infinity symbol (representing many)
Figure 3-5 A one-to-many relationship
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Many-to-Many Relationships
In the many-to-many relationship, any row in the first table can have matches to many rows in the second table Additionally, any row in the second table can have matches to many rows in the first table Consider a publishing database We could have a Book table listing titles and information on books, and an Author table holding information on authors We can see this in Figure 3-6
Figure 3-6 The Author and Book tables without a relationship
However, let s think about actual books and authors for a minute Any book could be written by multiple authors, and any author could write multiple books If we created a one-to-many relationship from the Book table to the Author table, it would work for a book with multiple authors, but any single author couldn t be related to multiple books Likewise, if we created a one-to-many relationship from the Author table to the Book table, it would work for an author writing multiple books, but not for a book with multiple authors We need to create a many-to-many relationship This is misleading though We can not directly create a many-to-many relationship between two tables Instead, we must define a third table (often referred to as a junction table) The junction table has a one-to-many relationship with the first table, and then a second one-to-many relationship with the second table We can see this in Figure 3-7
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