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CHAPTER 6 FUNCTIONS AND ARRAYS
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[2002, 72, 89], [2001, 62, 100], [2000, 69, 93], [1999, 78, 83], [1998, 69, 93], [1997, 79, 83], [1996, 73, 89], [1995, 58, 86], [1994, 53, 61], [1993, 75, 87]]; console.dir(pirates.shift());
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Figure 6 24. shift() removes and returns the first element in an array. Note that shift() modifies pirates, too, by shifting the contents down one place in the array every time it is invoked. This means that element 0 is removed, element 1 becomes element 0, and so on. So, after invoking shift() three times in a row, pirates has just 15 elements rather than 18 as Figure 6 25 displays. var pirates = [[2010, 57, 105], [2009, 62, 99], [2008, 67, 95], [2007, 68, 94], [2006, 67, 95], [2005, 67, 95], [2004, 72, 89], [2003, 75, 87], [2002, 72, 89], [2001, 62, 100], [2000, 69, 93], [1999, 78, 83],
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[1998, 69, 93], [1997, 79, 83], [1996, 73, 89], [1995, 58, 86], [1994, 53, 61], [1993, 75, 87]]; pirates.shift(), pirates.shift(), pirates.shift(), console.dir(pirates);
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Figure 6 25. pirates has 15 elements rather than 18 after invoking its shift() method three times. Naturally, JavaScript provides a method to pluck the last element from an array, which is named pop(). So, invoking pop() on pirates three times in a row removes and returns the 1993, 1994, and 1995 seasons, as Figure 6 26 displays. var pirates = [[2010, 57, 105], [2009, 62, 99], [2008, 67, 95], [2007, 68, 94], [2006, 67, 95], [2005, 67, 95], [2004, 72, 89], [2003, 75, 87], [2002, 72, 89], [2001, 62, 100], [2000, 69, 93], [1999, 78, 83], [1998, 69, 93], [1997, 79, 83],
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[1996, 73, 89], [1995, 58, 86], [1994, 53, 61], [1993, 75, 87]]; console.dir(pirates.pop()), console.dir(pirates.pop()), console.dir(pirates.pop());
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Figure 6 26. pop() removes and returns the last element in an array. Note that, like shift(), pop() modifies the array it is invoked upon. So, after invoking pop() three times on pirates, there are just 15 elements left as Figure 6 27 displays: var pirates = [[2010, 57, 105], [2009, 62, 99], [2008, 67, 95], [2007, 68, 94], [2006, 67, 95], [2005, 67, 95], [2004, 72, 89], [2003, 75, 87], [2002, 72, 89], [2001, 62, 100], [2000, 69, 93], [1999, 78, 83], [1998, 69, 93], [1997, 79, 83], [1996, 73, 89], [1995, 58, 86], [1994, 53, 61], [1993, 75, 87]];
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pirates.pop(), pirates.pop(), pirates.pop(), console.dir(pirates);
Figure 6 27. pirates has 15 elements rather than 18 after invoking its pop() method three times.
Adding Elements to an Array
To do the inverse of shift(), which is to say add an element to the beginning of an array, call an array s unshift() method. The Pirates hired a new manager, Clint Hurdle, for 2011. So I m hopeful they ll win say 15 more games than in 2010. Let s add that prediction of 72 wins and 90 losses to pirates by invoking its unshift() method. Then pass pirates to console.dir() and JavaScript will print the modified array in Firebug as Figure 6 28 displays. var pirates = [[2010, 57, 105], [2009, 62, 99], [2008, 67, 95], [2007, 68, 94], [2006, 67, 95], [2005, 67, 95], [2004, 72, 89], [2003, 75, 87], [2002, 72, 89], [2001, 62, 100], [2000, 69, 93], [1999, 78, 83], [1998, 69, 93], [1997, 79, 83], [1996, 73, 89],
CHAPTER 6 FUNCTIONS AND ARRAYS
[1995, 58, 86], [1994, 53, 61], [1993, 75, 87]]; pirates.unshift([2011, 72, 90]), console.dir(pirates);
Figure 6 28. unshift() adds an element to the beginning of an array. Similarly, pop() has an inverse, too. But it s not named unpop(), but push(). So let s add the 1992, 1991, and 1990 glory years to pirates by calling push() three times in a row. Then pass pirates to console.dir(), verifying our work with Figure 6 29. var pirates = [[2010, 57, 105], [2009, 62, 99], [2008, 67, 95], [2007, 68, 94], [2006, 67, 95], [2005, 67, 95], [2004, 72, 89], [2003, 75, 87], [2002, 72, 89], [2001, 62, 100], [2000, 69, 93], [1999, 78, 83], [1998, 69, 93], [1997, 79, 83],
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