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Older computers (like the Apple IIe, for example) represented an address using 2 bytes (16 bits) of memory, yielding a range of addresses from 0 to 216 1 = 65,535. Imagine having to fit your operating system, as well as all your applications in a mere 64 kilobytes of RAM (1 kilobyte = 1,024 bytes). Years later, when the Mac first appeared, it came with 128 kilobytes of RAM and used 24-bit memory addresses, yielding a range of addresses from 0 to 224 1 = 16,777,215 (also known as 16 megabytes). Back then, no one could imagine a computer that actually included 16 entire megabytes of memory! Of course, these days we are much smarter. We absolutely know for a fact that we ll never exceed the need for 64-bit addresses, right Hmm, better not count on that. In fact, if you are a betting person, I d wager that someday we ll see 16-byte addresses. Really!
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CHAPTER 7: Pointers and Parameters
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Once memory is allocated for myVar and myPointer, we move on to the statement:
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myPointer = &myVar;
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The 4-byte address of the variable myVar is written to the 4 bytes allocated to myPointer. In our example, myVar s address is 836. Figure 7-6 shows the value 836 stored in myPointer s 4 bytes. Now, myPointer is said to point to myVar.
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1,073,741,823 1,073,741,822 32,107 32,106 32,105 32,104 839 838 837 836 1 0
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Figure 7-6. The address of myVar is assigned to myPointer. In our example, the address of myVar is 836. The value 836 is stored in the memory allocated for the variable myPointer.
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int *myPointer;
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int myVar;
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OK, we re almost there. The next line of our example writes the value 27 to the location pointed to by myPointer:
*myPointer = 27;
CHAPTER 7: Pointers and Parameters
Without the * operator, the computer would place the value 27 in the memory allocated to myPointer. The * operator dereferences myPointer. Dereferencing a pointer turns the pointer into the variable it points to. Figure 7-7 shows the end results.
1,073,741,823 1,073,741,822 32,107 32,106 32,105 32,104 839 838 837 836 1 0
Figure 7-7. Finally, the value 27 is assigned to *myPointer.
int *myPointer;
int myVar;
If the concept of pointers seems alien to you, don t worry. You are not alone. Programming with pointers is one of the most difficult topics you ll ever take on. Just keep reading, and make sure you follow each of the examples line by line. By the end of the chapter, you ll be a pointer expert!
Function Parameters
One of the most important uses of pointers (and perhaps the easiest to understand) lies in the implementation of function parameters. In this section, we ll focus on parameters and, at the same time, have a chance to check out pointers in action.
CHAPTER 7: Pointers and Parameters
What Are Function Parameters
A function parameter is your chance to share a variable between a calling function and the called function. Suppose you wanted to write a function called AddTwo() that took two numbers, added them together, and returned the sum of the two numbers. How would you get the two original numbers into AddTwo() How would you get the sum of the two numbers back to the function that called AddTwo() As you might have guessed, the answer to both questions lies in the use of parameters. Before you can learn how to use parameters, however, you ll have to first understand the concept of scope.
Variable Scope
In C, every variable is said to have a scope, or range. A variable s scope defines where in the program you have access to a variable. In other words, if a variable is declared inside one function, can another function refer to that same variable C defines variable scope thusly: a variable declared inside a function is local to that function and may only be referenced inside that function. This definition is important. It means you can t declare a variable inside one function, and then refer to that same value inside another function. Here s an example that will never compile:
#include <stdio.h> int main (int argc, const char * argv[]) { int numDots; numDots = 500; DrawDots(); return 0; } void int DrawDots( void ) { i;
for ( i = 1; i <= numDots; i++ ) printf( "." ); }
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