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OCA/OCP Oracle Database 11g All-in-One Exam Guide
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To insert many rows with one INSERT command, the values for the rows must come from a query The syntax is as follows:
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INSERT INTO table [column [, column] ] subquery;
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Note that this syntax does not use the VALUES keyword If the column list is omitted, then the subquery must provide values for every column in the table To copy every row from one table to another, if the tables have the same column structure, a command such as this is all that is needed:
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insert into regions_copy select * from regions;
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This presupposes that the table REGIONS_COPY does exist The SELECT subquery reads every row from the source table, which is REGIONS, and the INSERT inserts them into the target table, which is REGIONS_COPY EXAM TIP Any SELECT statement, specified as a subquery, can be used as the source of rows passed to an INSERT This enables insertion of many rows Alternatively, using the VALUES clause will insert one row The values can be literals or prompted for as substitution variables To conclude the description of the INSERT command, it should be mentioned that it is possible to insert rows into several tables with one statement This is not part of the OCP examination, but for completeness here is an example:
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insert all when 1=1 then into emp_no_name (department_id,job_id,salary,commission_pct,hire_date) values (department_id,job_id,salary,commission_pct,hire_date) when department_id <> 80 then into emp_non_sales (employee_id,department_id,salary,hire_date) values (employee_id,department_id,salary,hire_date) when department_id = 80 then into emp_sales (employee_id,salary,commission_pct,hire_date) values (employee_id,salary,commission_pct,hire_date) select employee_id,department_id,job_id,salary,commission_pct,hire_date from employees where hire_date > sysdate - 30;
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To read this statement, start at the bottom The subquery retrieves all employees recruited in the last 30 days Then go to the top The ALL keyword means that every row selected will be considered for insertion into all the tables following, not just into the first table for which the condition applies The first condition is 1=1, which is always true, so every source row will create a row in EMP_NO_NAME This is a copy of the EMPLOYEES table with the personal identifiers removed The second condition is DEPARTMENT_ID <> 80, which will generate a row in EMP_NON_SALES for every employee who is not in the sales department; there is no need for this table to have the COMMISSION_PCT column The third condition generates a row in EMP_SALES
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8: DML and Concurrency
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for all the salesmen; there is no need for the DEPARTMENT_ID column, because they will all be in department 80 This is a simple example of a multitable insert, but it should be apparent that with one statement, and therefore only one pass through the source data, it is possible to populate many target tables This can take an enormous amount of strain off the database PART II Exercise 8-1: Use the INSERT Command techniques to insert rows into a table In this exercise, use various
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1 Connect to the WEBSTORE schema with either SQL Developer or SQL*Plus 2 Query the PRODUCTS, ORDERS, and ORDER_ITEMS tables, to confirm what data is currently stored:
select * from products; select * from orders; select * from order_items;
3 Insert two rows into the PRODUCTS table, providing the values in line:
insert into products values (prod_seqnextval, '11G SQL Exam Guide', 'ACTIVE',60,sysdate, 20); insert into products values (prod_seqnextval, '11G All-in-One Guide', 'ACTIVE',100,sysdate, 40);
4 Insert two rows into the ORDERS table, explicitly providing the column names:
insert values insert values into orders (order_id, order_date, order_status, order_amount, customer_id) (order_seqnextval, sysdate, 'COMPLETE', 3, 2); into orders (order_id, order_date, order_status, order_amount, customer_id) (order_seqnextval, sysdate, 'PENDING', 5, 3);
5 Insert three rows into the ORDER_ITEMS table, using substitution variables:
insert into order_items values (&item_id, &order_id, &product_id, &quantity);
When prompted, provide the values: {1, 1, 2,5}, {2,1,1,3}, and {1,2,2,4} 6 Insert a row into the PRODUCTS table, calculating the PRODUCT_ID to be 100 higher than the current high value This will need a scalar subquery:
insert into products values ((select max(product_id)+100 from products), '11G DBA2 Exam Guide', 'INACTIVE', 40, sysdate-365, 0);
7 Confirm the insertion of the rows:
select * from products; select * from orders; select * from order_items;
8 Commit the insertions:
commit;
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