Checking Date Validity in VS .NET

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33 Checking Date Validity
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Use PHP s checkdate() function:
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< php // check date 31-Apr-2006 // result: "Invalid date" echo checkdate(31,4,2006) "Valid date" : "Invalid date"; >
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Applications that accept date input from a user must validate this input before using it for calculations or date operations The checkdate() function simplifies this task considerably It accepts a series of three arguments, representing day, month and year, and returns a Boolean value indicating whether the combination make up a legal date An alternative way of accomplishing the same thing can be found in the PEAR Calendar class, available from http://pearphpnet/package/Calendar This class offers an isValid() method to test the validity of a particular date value The following listing illustrates this:
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< php // include Calendar class include "Calendar/Dayphp"; // initialize Day object to 31-Apr-2006 $day = & new Calendar_Day(2006, 4, 31); // check date // result: "Invalid date" echo $day->isValid() "Valid date" : "Invalid date"; >
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34 Converting Strings to Timestamps
Problem
You want to convert a string, encapsulating a date or time value, into the corresponding UNIX timestamp
Solution
Use PHP s strtotime() function:
< php // define string $str = "20030607"; // convert string to timestamp $ts = strtotime($str);
3: Working with Dates and Times
// format as readable date/time value // result: "Saturday, 07 June 2003 12:00:00 AM" (example) echo ($ts === -1) "Invalid string" : date("l, d F Y h:i:s A", $ts); >
Comments
PHP s strtotime() function performs the very important function of converting a human-readable date value into a UNIX timestamp, with minimal calculation required on the part of the application The date value can be any Englishlanguage date descriptor; strtotime() will attempt to identify it and return the corresponding timestamp If strtotime() cannot convert the description to a timestamp, it will return 1 In addition to date strings, the strtotime() function also accepts Englishlanguage time descriptors like now, next Wednesday, or last Friday, and you can use it to perform rudimentary date arithmetic The following listing illustrates this:
< php // assume now is "Monday, 30 October 2006 02:56:34 PM" // define string $str = "next Friday"; // convert string to timestamp $ts = strtotime($str); // format as readable date/time value // result: "Friday, 03 November 2006 12:00:00 AM" echo ($ts === false) "Invalid string" : date("l, d F Y h:i:s A", $ts); // define string $str = "2 weeks 6 hours ago"; // convert string to timestamp $ts = strtotime($str); // format as readable date/time value // result: "Monday, 16 October 2006 08:56:34 AM" echo ($ts === false) "Invalid string" : date("l, d F Y h:i:s A", $ts); >
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For more sophisticated date arithmetic, take a look at the listing in 316: Performing Date Arithmetic Read more strtotime() examples in the PHP manual at http://www
phpnet/strtotime
35 Checking for Leap Years
Problem
You want to check if a particular year is a leap year
Solution
Write a function to see if the year number is divisible by 4 or 400, but not 100:
< php // function to test if leap year function testLeapYear($year) { $ret = (($year%400 == 0) || ($year%4 == 0 && $year%100 != 0)) true : false; return $ret; } // result: "Is a leap year" echo testLeapYear(2004) "Is a leap year" : "Is not a leap year"; // result: "Is not a leap year" echo testLeapYear(2001) "Is a leap year" : "Is not a leap year"; >
Comments
A year is a leap year if it is fully divisible by 400, or by 4 but not 100 The function testLeapYear() in the previous listing encapsulates this logic, using PHP s % operator to check for divisibility, and returns a Boolean value indicating the result
3: Working with Dates and Times
An alternative way to do this is to use the checkdate() function to test for the presence of an extra day in February of that year The following listing illustrates this:
< php // function to test if leap year function testLeapYear($year) { return checkdate(2, 29, $year); } // result: "Is a leap year" echo testLeapYear(2004) "Is a leap year" : "Is not a leap year"; // result: "Is not a leap year" echo testLeapYear(2001) "Is a leap year" : "Is not a leap year"; >
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