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Workaround 2/2 Using Crossjoin
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If your data is not contiguous, you might want to combine a Crossjoin with the ParallelPeriod function
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-- workaround 2/2 crossjoin with member [Measures][Year Ago] as ([Measures][Reseller Sales Amount], Parallelperiod([Date][Calendar][Calendar Year],1, [Date][Calendar]currentmember)),format_string = "Currency" select {[Measures][Reseller Sales Amount],[Measures][Year Ago]} on columns, crossjoin([Date][Calendar Year][Calendar Year], [Date][Calendar Quarter of Year][Calendar Quarter of Year]) on rows from [Adventure Works]
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This should always give you the desired results The Crossjoin forces ParallelPeriod to behave as you might expect it
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Practical MDX Queries for Microsoft SQL Ser ver Analysis Ser vices 2008
his is a wide-ranging chapter on working with sets and members of sets By the end of the chapter, you ll be able to create, visualize, and manipulate sets
Key concepts Named sets, joining sets, set operations, extracting members, missing members, member properties, visual totals Keywords Distinct, item, Generate, Rank, Union, Intersect, Except, With Set, Head, Subset, Tail, VisualTotals, Create Set, Extract, Exists, Count, count
Distinct
When you have duplicate members returned by a query, you can suppress the duplicates with Distinct Here are two queries for you to try
Syntax
-- distinct 1/2 select {[Geography][Country][Australia],[Geography][Country] [Australia]} on columns from [Adventure Works] -- distinct 2/2 select distinct {[Geography][Country][Australia], [Geography][Country][Australia]} on columns from [Adventure Works]
Result
Analysis
Not terribly useful as it stands you are unlikely to ask for Australia twice However, this chapter includes many advanced set operations, and the members returned are not always explicitly defined In those cases, Distinct is very handy for removing duplication in the result
C h a p te r 9 : Ve n n D i a g ra m s : V i s u a l i z i n g a n d M a n i p u l a t i n g S e t s
Item on a Set
The Item property member performed against a set returns a tuple within the set What is the third calendar year in our Date dimension
Syntax
-- item on a set returns a tuple select [Date][Calendar][Calendar Year]item(2) on columns from [Adventure Works] -- alternative (2)Syntax select [Date][Calendar][Calendar Year]members(2) on columns from [Adventure Works]
Result
Analysis
Both queries give the same result Here we are returning the third calendar year Item is zero based
Item on a Tuple
Sometimes you may want to select a particular item (based on position) within a tuple
Syntax
-- item on a tuple returns a member select ([Date][Calendar]defaultmember, [Product][Product Categories]defaultmember)item(1) on columns from [Adventure Works]
Practical MDX Queries for Microsoft SQL Ser ver Analysis Ser vices 2008
Result
Analysis
The tuple has two members Item is zero based and item(1) returns the second member, which is All Products
Generate
If you want to perform the same operation against two or more sets, Generate may be of help
Syntax
-- generate with set [Bikes and Clothing] as {[Product][Product Categories][Category][Bikes], [Product][Product Categories][Category][Clothing]} set [Two Families] as generate({[Bikes and Clothing]}, [Product][Product Categories]currentmemberchildren) select [Two Families] on columns from [Adventure Works]
Result
Analysis
Generate is not the easiest of the MDX syntax Here, Generate creates a set called Two Families, which is projected along the Columns axis Generate operates on a set called Bikes and Clothing and returns the children of that set This is quite useful because children normally only works directly on an individual member, not a set By using Generate, we are able to have children apply against the members in the Bikes and Clothing set one at a time The result is all the children of both Bikes and Clothing
C h a p te r 9 : Ve n n D i a g ra m s : V i s u a l i z i n g a n d M a n i p u l a t i n g S e t s
Rank
Where do we sell the most, and what position is each city in the rankings
Syntax
-- rank with set [Countries and Cities] as {crossjoin([Customer][Country][Country],filter([Customer][City][City], [Measures][Internet Sales Amount] > 0))} member [Measures][Ranking] as rank([Customer][City]currentmember, [Customer][City]currentmembersiblings,[Measures] [Internet Sales Amount]) select {[Measures][Internet Sales Amount],[Measures][Ranking]} on columns, order([Countries and Cities],[Measures][Internet Sales Amount],bdesc) on rows from [Adventure Works]
Result
Analysis
An Order function is used to sort the rows with the highest sales at the top The result of the Rank function is shown in the second column Rank compares a city against all its siblings For example, Bendigo in Australia comes in at number 5 If the third parameter for Rank is omitted, the ranking is based on the position of the first parameter in the second set parameter; in this case, Bendigo comes in at number 31
Practical MDX Queries for Microsoft SQL Ser ver Analysis Ser vices 2008
Union, Intersect, Except Base Query 1/2
Some of the fundamental set operators are Union, Intersect, and Except To investigate their use, we need two base queries This is the first of the two
Syntax
-- best cities in 2003 with set [Best Cities in CY 2003] as order(topcount([Customer][Customer Geography][City],10, ([Measures][Internet Sales Amount], [Date][Calendar][Calendar Year][CY 2003])), [Measures][Internet Sales Amount],bdesc) select [Measures][Internet Sales Amount] on columns, [Best Cities in CY 2003] on rows from [Adventure Works] where [Date][Calendar][Calendar Year][CY 2003]
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