# qr code vb.net open source y 6 4 2 x 6 4 2 2 4 6 2 4 6 in Visual Studio .NET Generate Code 39 Extended in Visual Studio .NET y 6 4 2 x 6 4 2 2 4 6 2 4 6

y 6 4 2 x 6 4 2 2 4 6 2 4 6
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Figure B-37
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Illustration for the solution to Problem 9 in Chap 18
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572 Worked-Out Solutions to Exercises: 11-19
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The object described by these equations is a circular helix having a radius of 2 units, and centered on the y axis Here are some values of x, y, and z that we can calculate as t varies, causing a point on the helix to complete a single revolution in a moving plane perpendicular to the y axis: When t = 0, we have x = 2, y = 0, and z = 0 When t = p /2, we have x = 0, y = 1/4, and z = 2 When t = p, we have x = 2, y = 1/2, and z = 0 When t = 3p /2, we have x = 0, y = 3/4, and z = 2 When t = 2p, we have x = 2, y = 1, and z = 0
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Every time t increases by 2p, our point makes exactly one revolution in a moving plane that s always perpendicular to the y axis In addition, we can see that every time t increases by 2p, our point gets 1 unit more distant from the xz plane in the +y direction The pitch of the helix is therefore 1 linear unit per revolution The sense of rotation is rather tricky to describe Suppose that we re somewhere on the y axis, and we direct our gaze in the y direction As the value of the parameter t increases, causing a point on the helix to move generally toward us, the point appears to revolve counterclockwise around the y axis The helix s sense of rotation is therefore counterclockwise in the +y direction Figure B-38 is a perspective drawing of the graph of this object in Cartesian xyz space
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Helix is centered on the y axis
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+y Helix turns counterclockwise as we move in the +y direction
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Pitch of helix =1
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Each axis division is 1 unit
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