 Home
 Products
 Integration
 Tutorial
 Barcode FAQ
 Purchase
 Company
vb.net generate qr code Cartesian TwoSpace in .NET
Cartesian TwoSpace Read Code 39 Full ASCII In .NET Using Barcode Control SDK for VS .NET Control to generate, create, read, scan barcode image in .NET applications. Code39 Printer In .NET Framework Using Barcode creator for VS .NET Control to generate, create Code 39 Full ASCII image in VS .NET applications. If you multiply both x and y by 1, P will move diagonally to the opposite quadrant It will, in effect, be reflected by both axes If P starts out in the first quadrant, it will move to the third If P starts out in the second quadrant, it will move to the fourth If P starts out in the third quadrant, it will move to the first If P starts out in the fourth quadrant, it will move to the second Code 3/9 Scanner In .NET Using Barcode scanner for VS .NET Control to read, scan read, scan image in VS .NET applications. Create Barcode In .NET Framework Using Barcode printer for .NET Control to generate, create barcode image in .NET framework applications. If you have trouble envisioning these point maneuvers, draw a Cartesian plane on a piece of graph paper Then plot a point or two in each quadrant Calculate how the x and y values change when you multiply either or both of them by 1, and then plot the new points Barcode Decoder In .NET Using Barcode recognizer for VS .NET Control to read, scan read, scan image in VS .NET applications. Printing Code 39 Full ASCII In Visual C#.NET Using Barcode maker for VS .NET Control to generate, create Code 39 Full ASCII image in .NET applications. Distance of a Point from Origin
Draw Code 3/9 In VS .NET Using Barcode maker for ASP.NET Control to generate, create Code39 image in ASP.NET applications. Print USS Code 39 In Visual Basic .NET Using Barcode drawer for VS .NET Control to generate, create Code 39 Extended image in VS .NET applications. On a straight number line, the distance of any point from the origin is equal to the absolute value of the number corresponding to the point In the Cartesian plane, the distance of a point from the origin depends on both of the numbers in the point s ordered pair Barcode Creation In Visual Studio .NET Using Barcode drawer for .NET Control to generate, create barcode image in .NET applications. Draw Bar Code In VS .NET Using Barcode creator for .NET framework Control to generate, create bar code image in VS .NET applications. An example Figure 14 shows the point (4,3) plotted in the Cartesian plane Suppose that we want to find the distance d of (4,3) from the origin (0,0) How can this be done We can calculate d using the Pythagorean theorem from geometry In case you ve forgotten that principle, here s a refresher Suppose we have a right triangle defined by points P, Q, and R Suppose the sides of the triangle have lengths b, h, and d as shown in Fig 15 Then Code128 Drawer In .NET Using Barcode encoder for VS .NET Control to generate, create Code128 image in .NET applications. ISSN  13 Generator In .NET Framework Using Barcode generation for Visual Studio .NET Control to generate, create International Standard Serial Number image in .NET applications. b2 + h2 = d 2 We can rewrite this as d = (b 2 + h 2)1/2 where the 1/2 power represents the nonnegative square root Now let s make the following point assignments between the situations of Figs 14 and 15: The origin in Fig 14 corresponds to the point Q in Fig 15 The point (4,0) in Fig 14 corresponds to the point R in Fig 15 The point (4,3) in Fig 14 corresponds to the point P in Fig 15 Continuing with this analogy, we can see the following facts: The line segment connecting the origin and (4,0) has length b = 4 The line segment connecting (4,0) and (4,3) has height h = 3 The line segment connecting the origin and (4,3) has length d (unknown) Making Code39 In None Using Barcode creation for Microsoft Word Control to generate, create ANSI/AIM Code 39 image in Office Word applications. Create GTIN  128 In Java Using Barcode creator for BIRT Control to generate, create GTIN  128 image in BIRT applications. Distance of a Point from Origin
Barcode Drawer In C#.NET Using Barcode encoder for .NET Control to generate, create bar code image in Visual Studio .NET applications. Drawing Code 128C In Java Using Barcode printer for Java Control to generate, create Code128 image in Java applications. y 6 4 2 Scan EAN 13 In None Using Barcode scanner for Software Control to read, scan read, scan image in Software applications. UCC  12 Reader In VB.NET Using Barcode scanner for Visual Studio .NET Control to read, scan read, scan image in Visual Studio .NET applications. (4, 3) d x
Bar Code Reader In Java Using Barcode Control SDK for Java Control to generate, create, read, scan barcode image in Java applications. Decode EAN128 In Visual Basic .NET Using Barcode reader for .NET Control to read, scan read, scan image in VS .NET applications. What s the distance d
2 4 6 (4, 0) Figure 14 We can use the Pythagorean theorem to find the distance d of the point (4,3) from the origin (0,0) in the Cartesian plane The side of the right triangle having length d is the longest side, called the hypotenuse Using the Pythagorean formula, we can calculate d = (b 2 + h 2)1/2 = (42 + 32)1/2 = (16 + 9)1/2 = 251/2 = 5 We ve determined that the point (4,3) is 5 units distant from the origin in Cartesian coordinates, as measured along a straight line connecting (4,3) and the origin Figure 15 The Pythagorean theorem for right triangles
Cartesian TwoSpace
The general formula We can generalize the previous example to get a formula for the distance of any point from the origin in the Cartesian plane In fact, we can repeat the explanation of the previous example almost verbatim, only with a few substitutions Consider a point P with coordinates (xp,yp) We want to calculate the straightline distance d of the point P from the origin (0,0), as shown in Fig 16 Once again, we use the Pythagorean theorem Turn back to Fig 15 and follow along by comparing with Fig 16: The origin in Fig 16 corresponds to the point Q in Fig 15 The point (xp,0) in Fig 16 corresponds to the point R in Fig 15 The point (xp,yp) in Fig 16 corresponds to the point P in Fig 15 The following facts are also visually evident: The line segment connecting the origin and (xp,0) has length b = xp The line segment connecting (xp,0) and (xp,yp) has height h = yp The line segment connecting the origin and (xp,yp) has length d (unknown) The Pythagorean formula tells us that d = (b 2 + h 2)1/2 = (xp2 + yp2)1/2

