vb.net barcode reader source code Determining the Conduction State of an Ideal Diode in Software

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EXAMPLE 81 Determining the Conduction State of an Ideal Diode
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Determine whether the ideal diode of Figure 815 is conducting
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R1 R2 VS
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Known Quantities: VS = 12 V; VB = 11 V; R1 = 5 Find: The conduction state of the diode Assumptions: Use the ideal diode model
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; R2 = 10
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; R3 = 10
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Figure 815 Analysis: Assume initially that the ideal diode does not conduct and replace it with an
_ v1 + vD v2 5 VS = 12 V 10 10 + VB = 11 V _
open circuit, as shown in Figure 816 The voltage across R2 can then be computed using the voltage divider rule: v1 = R2 10 12 = 8 V VS = R1 + R 2 5 + 10
+ 8V _
Applying KVL to the right-hand-side mesh (and observing that no current ows in the circuit since the diode is assumed off), we obtain: v1 = vD + VB or vD = 8 11 = 3 V
The result indicates that the diode is reverse-biased, and con rms the initial assumption Thus, the diode is not conducting As further illustration, let us make the opposite assumption, and assume that the diode conducts In this case, we should replace the diode with a short circuit, as shown in Figure 817 The resulting circuit is solved by nodal analysis, noting that v1 = v2 since the
Part II
Electronics
_ v1 + vD v2 5 i D = i2 10
diode is assumed to act as a short circuit v1 v1 VB VS v 1 = + R1 R2 R3 VB v1 v1 v1 VS + = + + R1 R3 R1 R2 R3 12 11 + = 5 10 1 1 1 + + v1 5 10 10
VS = 12 V
10
+ VB = 11 V _
v1 = 25(24 + 11) = 875V Since v1 = v2 < VB = 11 V, we must conclude that current is owing in the reverse direction (from VB to node v2 /v1 ) through the diode This observation is inconsistent with the initial assumption, since if the diode were conducting, we can see current ow only in the forward direction Thus, the initial assumption was incorrect, and we must conclude that the diode is not conducting
Comments: The formulation of diode problems illustrated in this example is based on Figure 817
making an initial assumption The assumption results in replacing the ideal diode with either a short or an open circuit Once this step is completed, the resulting circuit is a linear circuit and can be solved by known methods to verify the consistency of the initial assumption
Focus on Computer-Aided Solution: The circuit of Figure 815 is simulated by
Electronics WorkbenchTM in the CD that accompanies the book Try changing the values of resistors in the simulation circuit to see if it is possible to cause the diode to conduct (Hint: Use a very large value for R2 ) Note that the computer simulation employs an ideal diode model, but could also use a physically correct model of the diode (that of equation 86) (click on the diode symbol to see the list of options)
Multisim
EXAMPLE 82 Determining the Conduction State of an Ideal Diode
Problem
Determine whether the ideal diode of Figure 818 is conducting
+ VS _
R2 + VB _
Solution
Known Quantities: VS = 12 V; VB = 11 V; R1 = 5 Find: The conduction state of the diode Assumptions: Use the ideal diode model Analysis: Assume initially that the ideal diode does not conduct and replace it with an
_ vD +
; R2 = 4
5 v1 + 12 V _ 4 + 11 V _
open circuit, as shown in Figure 819 The current owing in the resulting series circuit (shown in Figure 819) is: i= VS VB 1 = A R1 + R 2 9
i = 1/9 A v D +
The voltage at node v1 is: v1 11 12 v1 = 5 4 v1 = 1144 V
8
Semiconductors and Diodes
The result indicates that the diode is strongly reverse-biased, since vD = 0 v1 = 1144 V, and con rms the initial assumption Thus, the diode is not conducting
Focus on Computer-Aided Solution: The circuit of Figure 818 is simulated by Electronics WorkbenchTM in the CD that accompanies the book Try changing the values of resistors in the simulation circuit to see if it is possible to cause the diode to conduct
+ vD _ + vL _
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