vb.net barcode reader source code Comments: The circuit examined in this example is not quite a practical transistor in Software

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Comments: The circuit examined in this example is not quite a practical transistor
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ampli er yet, but it demonstrates most of the essential features of BJT ampli ers We summarize them as follows
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Transistor ampli er analysis is greatly simpli ed by considering the DC bias circuit and the AC equivalent circuits separately This is an application of the principle of superposition Once the bias point (or DC operating or quiescent point) has been determined, the current gain of the transistor can be determined from the collector characteristic curves This gain is somewhat dependent on the location of the operating point The AC voltage gain of the ampli er is strongly dependent on the base and collector resistance values Note that the AC voltage gain is negative! This corresponds to a 180 phase inversion if the signal to be ampli ed is a sinusoid
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Many issues remain to be considered before we can think of designing and analyzing a practical transistor ampli er It is extremely important that you master this example before studying the remainder of the section
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Focus on Computer-Aided Tools: An Electronics WorkbenchTM simulation of the circuit
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analyzed in this example is available in the CD-ROM that accompanies the book Run the simulation to see the effect of the negative voltage gain on the output signal waveform
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In discussing the DC biasing procedure for the BJT, we pointed out that the simple circuit of Figure 912 would not be a practical one to use in an application
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circuit In fact, the more realistic circuit of Example 94 is also not a practical biasing circuit The reasons for this statement are that two different supplies are required (VCC and VBB ) a requirement that is not very practical and that the resulting DC bias (operating) point is not very stable This latter point may be made clearer by pointing out that the location of the operating point could vary signi cantly if, say, the current gain of the transistor, , were to vary from device to device A circuit that provides great improvement on both counts is shown in Figure 920 Observe, rst, that the voltage supply, VCC , appears across the pair of resistors R1 and R2 , and that therefore the base terminal for the transistor will see the Th venin equivalent circuit composed of the equivalent voltage source, e VBB = R2 VCC R1 + R 2 R2 (96)
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IC R1 IB + VBE RC + VCE IE RE VCC
and of the equivalent resistance, RB = R1 (97)
Figure 921(b) shows a redrawn DC bias circuit that makes this observation more evident The circuit to the left of the dashed line in Figure 921(a) is represented in Figure 921(b) by the equivalent circuit composed of VBB and RB
IC IC
Figure 920 Practical BJT self-bias DC circuit
IB + VBE _ RE
+ RC VCE _ IE VCC
IB RB VBB + VBE _ RE
+ R C VCE _ IE VCC
VCC R2
Figure 921 DC self-bias circuit represented in equivalent-circuit form
Recalling that the BE junction acts much as a diode, the following equations describe the DC operating point of the self-bias circuit Around the base-emitter circuit, VBB = IB RB + VBE + IE RE = [RB + ( + 1)RE ]IB + VBE (98) where VBE is the BE junction voltage (diode forward voltage) and IE = ( +1)IB Around the collector circuit, on the other hand, the following equation applies: VCC = IC RC + VCE + IE RE = IC RC + since IE = IB + IC = ( 1 + 1)IC +1 RE + VCE (99)
These two equations may be solved to obtain: (1) an expression for the base current, IB = VBB VBE RB + ( + 1)RE (910)
9
Transistor Fundamentals
from which the collector current can be determined as IC = IB ; and (2) an expression for the collector-emitter voltage: VCE = VCC IC RC + +1 RE (911)
This last equation is the load-line equation for the bias circuit Note that the effective load resistance seen by the DC collector circuit is no longer just RC , but is now given by RC + +1 RE RC + RE
The following example provides a numerical illustration of the analysis of a DC self-bias circuit for a BJT
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