barcode reader in asp.net codeproject Electronic Instrumentation and Measurements in Software

Drawing Quick Response Code in Software Electronic Instrumentation and Measurements

15
Decode Quick Response Code In None
Using Barcode Control SDK for Software Control to generate, create, read, scan barcode image in Software applications.
Print QR Code In None
Using Barcode drawer for Software Control to generate, create Denso QR Bar Code image in Software applications.
Electronic Instrumentation and Measurements
Read QR In None
Using Barcode reader for Software Control to read, scan read, scan image in Software applications.
QR Code Generator In Visual C#.NET
Using Barcode printer for Visual Studio .NET Control to generate, create QR Code 2d barcode image in .NET framework applications.
or 1 + Q C2 1 4 + 4(K 1) 2 Q C1 2 C2 C1
Denso QR Bar Code Generation In .NET
Using Barcode generator for ASP.NET Control to generate, create QR Code JIS X 0510 image in ASP.NET applications.
QR Code 2d Barcode Drawer In .NET
Using Barcode generation for .NET Control to generate, create Quick Response Code image in .NET applications.
R2 = R1
QR Code ISO/IEC18004 Encoder In Visual Basic .NET
Using Barcode generation for .NET Control to generate, create QR Code JIS X 0510 image in VS .NET applications.
Data Matrix Maker In None
Using Barcode generation for Software Control to generate, create ECC200 image in Software applications.
Now, we have the new system: 1 C2 1 + 4 + 4(K 1) 2 R Q Q C1 2 = R1 C2 2 C1 1 R1 R2 = wC C1 C2 that can by easily be solved by substitution, as follows: 1 + Q C2 1 4 + 4(K 1) 2 Q C1 C2 2 C1 1 + Q C2 1 4 + 4(K 1) 2 Q C1 2 That is, 2 R1 = C C1 C2 1 + Q 1 + Q C2 C1 C2 C1
Bar Code Printer In None
Using Barcode generation for Software Control to generate, create bar code image in Software applications.
EAN128 Maker In None
Using Barcode drawer for Software Control to generate, create UCC.EAN - 128 image in Software applications.
R2 =
Code 39 Extended Creator In None
Using Barcode creator for Software Control to generate, create USS Code 39 image in Software applications.
Paint Bar Code In None
Using Barcode creation for Software Control to generate, create bar code image in Software applications.
R1
2 Of 5 Standard Printer In None
Using Barcode drawer for Software Control to generate, create 2 of 5 Industrial image in Software applications.
Painting Bar Code In Objective-C
Using Barcode printer for iPhone Control to generate, create bar code image in iPhone applications.
1 C C1 C 2
Bar Code Creator In Visual Studio .NET
Using Barcode creation for ASP.NET Control to generate, create bar code image in ASP.NET applications.
Encode Bar Code In VB.NET
Using Barcode generator for VS .NET Control to generate, create barcode image in .NET framework applications.
C2 1 4 + 4(K 1) Q2 C1
USS Code 39 Scanner In None
Using Barcode scanner for Software Control to read, scan read, scan image in Software applications.
Linear 1D Barcode Drawer In C#.NET
Using Barcode drawer for Visual Studio .NET Control to generate, create Linear image in Visual Studio .NET applications.
R2 =
ECC200 Recognizer In Java
Using Barcode decoder for Java Control to read, scan read, scan image in Java applications.
Create Code 128 In Java
Using Barcode maker for Android Control to generate, create Code 128B image in Android applications.
C2 1 4 + 4(K 1) Q2 C1 2 C2 C C1 C 2 C1
If we assume 01 F values for both C1 and C2 in each section, we can compute the value of the resistances required to complete the design: First section: R1 = 7,723 (nearest standard 5% resistor value: 82 k ) R2 = 80,923 (nearest standard 5% resistor value: 82 k ) Second section: R1 = 6,411 (nearest standard 5% resistor value: 68 k ) R2 = 97,484 (nearest standard 5% resistor value: 100 k )
Part II
Electronics
The designer may choose to employ high precision resistors or adjustable resistors, if desired
Comments: We have chosen to x the values of the capacitors and compute the required values of the resistors because of the greater availability of resistor sizes Focus on Computer-Aided Solutions: A Matlab le that performs the computations
shown above for each quadratic section may be found in the accompanying CD-ROM Note that the m- le can be easily modi ed to design a Butterworth lter of arbitrary order
Check Your Understanding
157 Determine the order of the lter required to satisfy the requirements of Example 153 if the stop-band frequency is moved to S = 2 C 158 What is the actual attenuation of the lter of Exercise 157 at the stop-band frequency, S 159 Design a quadratic lter section with Q = 1 and a cutoff frequency of 10 rad/s Note that there can be many solutions, depending on your design
ANALOG-TO-DIGITAL AND DIGITAL-TO-ANALOG CONVERSION
To take advantage of the capabilities of a microcomputer, it is necessary to suitably interface signals to and from external devices with the microcomputer Depending on the nature of the signal, either an analog or a digital interface circuit will be required The advantages in memory storage, programming exibility, and computational power afforded by today s digital computers are such that the instrumentation designer often chooses to convert an analog signal to an equivalent digital representation, to exploit the capabilities of a microprocessor in processing the signal In many cases, the data converted from analog to digital form remain in digital form for ease of storage, or for further processing In some instances it is necessary to convert the data back to analog form The latter condition arises frequently in the context of control system design, where an analog measurement is converted to digital form and processed by a digital computer to generate a control action (eg, raising or lowering the temperature of a process, or exerting a force or a torque); in such cases, the output of the digital computer is converted back to analog form, so that a continuous signal becomes available to the actuators Figure 1523 illustrates the general appearance of a digital measuring instrument and of a digital controller acting on a plant or process The objective of this section is to describe how the digital-to-analog (D/A) and analog-to-digital (A/D) conversion blocks of Figure 1523 function After illustrating discrete circuits that can implement simple A/D and D/A converters, we shall emphasize the use of ICs specially made for these tasks Nowadays, it is uncommon (and impractical) to design such circuits using discrete components:
15
Electronic Instrumentation and Measurements
Sensor
A/D converter
Digital signal processor
Display
Digital measuring instrument Analog control signal Analog measurement
Plant or process
Sensors
D/A converter
Digital controller
A/D converter
Control strategy Digital control system
Figure 1523 Block diagrams of a digital measuring instrument and a digital control system
the performance and ease of use of IC packages make them the preferred choice in virtually all applications Digital-to-Analog Converters We discuss digital-to-analog conversion rst because it is a necessary part of analog-to-digital conversion in many A/D conversion schemes A digital-toanalog converter (DAC) will convert a binary word to an analog output voltage (or current) The binary word is represented in terms of 1s and 0s, where typically (but not necessarily), 1s correspond to a 5-volt level and 0s to a 0-volt signal As an example, consider a four-bit binary word: B = (b3 b2 b1 b0 )2 = (b3 23 + b2 22 + b1 21 + b0 20 )10 The analog voltage corresponding to the digital word B would be va = (8b3 + 4b2 + 2b1 + b0 ) v (1522) (1521)
where v is the smallest step size by which va can increment This least step size will occur whenever the least signi cant bit (LSB), b0 , changes from 0 to 1, and is the smallest increment the digital number can make We shall also shortly see that the analog voltage obtained by the D/A conversion process has a staircase appearance because of the discrete nature of the binary signal The step size is determined on the basis of each given application, and is usually determined on the basis of the number of bits in the digital word to be converted to an analog voltage We can see that, by extending the previous example for an n-bit word, the maximum value va can attain is va max = (2n 1 + 2n 2 + + 21 + 20 ) v = (2n 1) v (1523)
Copyright © OnBarcode.com . All rights reserved.