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barcode reader in asp.net codeproject Part III in Software
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Principles of Electromechanics
EXAMPLE 162 Analysis of Magnetic Structure and Equivalent Magnetic Circuit
Problem
i= 01 A N turns h
Calculate the ux, ux density, and eld intensity on the magnetic structure of Figure 1614
Solution
Known Quantities: Relative permeability; number of coil turns; coil current; structure
geometry
Find: ; B; H Schematics, Diagrams, Circuits, and Given Data: r = 1,000; N = 500 turns; i = 01 A The magnetic circuit geometry is de ned in Figures 1614 and 1615 Assumptions: All magnetic ux is linked by the coil; the ux is con ned to the magnetic core; the ux density is uniform Analysis: l = 01 m, h = 01 m, w = 001 m
Calculation of magnetomotive force From equation 1628, we calculate the magnetomotive force: F = mmf = N i = (500 turns)(01 A) = 50 A t Mean path
Calculation of mean path Next, we estimate the mean path of the magnetic ux On the basis of the assumptions, we can calculate a mean path that runs through the geometric center of the magnetic structure, as shown in Figure 1615 The path length is: lc = 4 009 m = 036 m 008 m 009 m
The cross sectional area is A = w 2 = (001)2 = 00001 m2 Calculation of reluctance Knowing the magnetic path length and cross sectional area we can calculate the reluctance of the circuit: lc lc 036 R= = = = 2865 106 A t/Wb A r 0 A 1,000 4 10 7 00001 The corresponding equivalent magnetic circuit is shown in Figure 1616 Calculation of magnetic ux, ux density and eld intensity On the basis of the assumptions, we can now calculate the magnetic ux: = 50 A t F = = 175 10 5 Wb R 2865 106 A t/Wb 01 m

