barcode reader code in c# net Part III in Software

Creator QR Code in Software Part III

Part III
Quick Response Code Recognizer In None
Using Barcode Control SDK for Software Control to generate, create, read, scan barcode image in Software applications.
Encoding Denso QR Bar Code In None
Using Barcode maker for Software Control to generate, create QR image in Software applications.
Electromechanics
Recognizing QR In None
Using Barcode recognizer for Software Control to read, scan read, scan image in Software applications.
Quick Response Code Generation In C#
Using Barcode encoder for .NET Control to generate, create QR Code image in VS .NET applications.
where k is a machine constant, IS is the rms value of the stator current, and If is the DC rotor current Now, the rotor angle can be expressed as a function of time by = 0 + m t (1762)
Denso QR Bar Code Encoder In VS .NET
Using Barcode encoder for ASP.NET Control to generate, create QR-Code image in ASP.NET applications.
Making QR In .NET Framework
Using Barcode creation for VS .NET Control to generate, create QR-Code image in .NET applications.
where 0 is the angular position of the rotor at t = 0; the torque expression then becomes T = k 2IS If sin( e t) sin( m t + 0 ) (1763) 2 IS If cos[( m e )t 0 ] cos[( m + e )t + 0 ] =k 2 It is a straightforward matter to show that the average value of this torque, T , is different from zero only if m = e , that is, only if the motor is turning at the synchronous speed The resulting average torque is then given by T = k 2IS If cos( 0 ) (1764) Note that equation 1763 corresponds to the sum of an average torque plus a uctuating component at twice the original electrical (or mechanical) frequency The uctuating component results because, in the foregoing derivation, a singlephase current was assumed The use of multiphase currents reduces the torque uctuation to zero and permits the generation of a constant torque A per-phase circuit model describing the synchronous motor is shown in Figure 1733, where the rotor circuit is represented by a eld winding equivalent resistance and inductance, Rf and Lf , respectively, and the stator circuit is represented by equivalent stator winding inductance and resistance, LS and RS , respectively, and by the induced emf, Eb From the exact equivalent circuit as given in Figure 1733, we have VS = Eb + IS (RS + j XS ) (1765)
QR Code 2d Barcode Generation In VB.NET
Using Barcode maker for VS .NET Control to generate, create QR Code JIS X 0510 image in Visual Studio .NET applications.
Print GS1 - 12 In None
Using Barcode maker for Software Control to generate, create Universal Product Code version A image in Software applications.
Lf If
Making ECC200 In None
Using Barcode printer for Software Control to generate, create Data Matrix image in Software applications.
Printing EAN 128 In None
Using Barcode generation for Software Control to generate, create GS1 128 image in Software applications.
Rf + RS + Eb
Printing Bar Code In None
Using Barcode maker for Software Control to generate, create bar code image in Software applications.
Paint Barcode In None
Using Barcode generator for Software Control to generate, create barcode image in Software applications.
Vf LS
Paint RM4SCC In None
Using Barcode creator for Software Control to generate, create RoyalMail4SCC image in Software applications.
Recognize USS Code 128 In None
Using Barcode scanner for Software Control to read, scan read, scan image in Software applications.
where XS is known as the synchronous reactance and includes magnetizing reactance The motor power is Pout = S T = |VS ||IS | cos( ) (1766)
Reading Code 128 Code Set B In .NET Framework
Using Barcode scanner for .NET Control to read, scan read, scan image in Visual Studio .NET applications.
ANSI/AIM Code 39 Decoder In None
Using Barcode decoder for Software Control to read, scan read, scan image in Software applications.
Is + VS 0
Paint Code-39 In Java
Using Barcode drawer for Eclipse BIRT Control to generate, create Code-39 image in Eclipse BIRT applications.
UCC.EAN - 128 Generation In VB.NET
Using Barcode generator for .NET framework Control to generate, create EAN 128 image in .NET framework applications.
for each phase, where T is the developed torque and is the angle between VS and IS When the phase winding resistance RS is neglected, the circuit model of a synchronous machine can be redrawn as shown in Figure 1734 The input power (per phase) is equal to the output power in this circuit, since no power is dissipated in the circuit; that is: P = Pin = Pout = |VS ||IS | cos( ) Also by inspection of Figure 1734, we have d = |Eb | sin( ) = |IS |XS cos( ) Then |Eb ||VS | sin( ) = |VS ||IS |XS cos( ) = XS P (1769) (1768) (1767)
Recognizing ANSI/AIM Code 39 In Visual C#.NET
Using Barcode recognizer for .NET framework Control to read, scan read, scan image in Visual Studio .NET applications.
GS1-128 Maker In Objective-C
Using Barcode generator for iPhone Control to generate, create USS-128 image in iPhone applications.
Figure 1733 Per-phase circuit model
IS + Eb
XS + VS 0
IS VS jISXS Eb d
17
Introduction to Electric Machines
P Pmax
Generator 180 90 90 Motor <0 180 3 Vs Eb XS
Pmax = Pmax
Figure 1735 Power versus power angle for a synchronous machine
The total power of a three-phase synchronous machine is then given by |VS ||Eb | sin( ) (1770) P = (3) XS Because of the dependence of the power upon the angle , this angle has come to be called the power angle If is zero, the synchronous machine cannot develop useful power The developed power has its maximum value at equal to 90 If we assume that |Eb | and |VS | are constant, we can draw the curve shown in Figure 1735, relating the power and power angle in a synchronous machine A synchronous generator is usually operated at a power angle varying from 15 to 25 For synchronous motors and small loads, is close to 0 , and the motor torque is just suf cient to overcome its own windage and friction losses; as the load increases, the rotor eld falls further out of phase with the stator eld (although the two are still rotating at the same speed), until reaches a maximum at 90 If the load torque exceeds the maximum torque, which is produced for = 90 , the motor is forced to slow down below synchronous speed This condition is undesirable, and provisions are usually made to shut the motor down automatically whenever synchronism is lost The maximum torque is called the pull-out torque and is an important measure of the performance of the synchronous motor Accounting for each of the phases, the total torque is given by m T = |VS ||IS | cos( ) (1771) s where m is the number of phases From Figure 1734, we have Eb sin( ) = XS IS cos( ) Therefore, for a three-phase machine, the developed torque is 3 |VS ||Eb | P = sin( ) N-m (1772) T = s s XS Typically, analysis of multiphase motors is performed on a per-phase basis, as illustrated in the examples that follow
Copyright © OnBarcode.com . All rights reserved.